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5) Please calculate the equilibrium constant of following reaction at 298 K. C3H6(g)+H2(g)=C3H$(g) If the feed gas contains C3H6 (30 mol %), H2 (40 mol %), C3H8(0.5 mol %), N2 (29.5 mol %), and the pressure of system is pº, can this reaction happen spontaneously? At 298 K C3H6 (g) C3H8 (g) H2(g) A,Hº (kJ•mol"') 20.42 - 103.85 se (J-K-'mol"') 266.90 269.90 130.5

5) Please calculate the equilibrium constant of following reaction at 298 K. C3H6(g)+H2(g)=C3H$(g) If the feed gas contains C3H6 (30 mol %), H2 (40 mol %), C3H8(0.5 mol %), N2 (29.5 mol %), and the pressure of system is pº, can this reaction happen spontaneously? At 298 K C3H6 (g) C3H8 (g) H2(g) A,Hº (kJ•mol"') 20.42 - 103.85 se (J-K-'mol"') 266.90 269.90 130.5

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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5) Please calculate the equilibrium constant of following reaction at 298 K. C3H6(g)+H2(g)=C3H$(g) If the feed gas contains C3H6 (30 mol %), H2 (40 mol %), C3H8(0.5 mol %), N2 (29.5 mol %), and the pressure of system is pº, can this reaction happen spontaneously? At 298 K C3H6 (g) C3H8 (g) H2(g) A,H (kJ mol-') 20.42 - 103.85 Se (J-K-'mol") 266.90 269.90 130.5
Transcribed Image Text:5) Please calculate the equilibrium constant of following reaction at 298 K. C3H6(g)+H2(g)=C3H$(g) If the feed gas contains C3H6 (30 mol %), H2 (40 mol %), C3H8(0.5 mol %), N2 (29.5 mol %), and the pressure of system is pº, can this reaction happen spontaneously? At 298 K C3H6 (g) C3H8 (g) H2(g) A,H (kJ mol-') 20.42 - 103.85 Se (J-K-'mol") 266.90 269.90 130.5
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