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5 ke Figure P3.3 10 Ω 2 k 6 kll 50 mA 10 kag 9 kng 18 kn 18 N 40 Ω (b) 5 V 100 Ωξ 25 Ω 22Ω3 600 0 2 kn 65 V 900 Ng 750 N3 500 ng $1.5 kn 3 kn (a) (c) 250 0 600 N 200 03 0.2 A(1) 300 g 150 Ω (d)

5 ke Figure P3.3 10 Ω 2 k 6 kll 50 mA 10 kag 9 kng 18 kn 18 N 40 Ω (b) 5 V 100 Ωξ 25 Ω 22Ω3 600 0 2 kn 65 V 900 Ng 750 N3 500 ng $1.5 kn 3 kn (a) (c) 250 0 600 N 200 03 0.2 A(1) 300 g 150 Ω (d)

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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For each of the circuits shown ,


1. a) find the equivalent resistance seen by the source,
2. b) find the power developed by the source.

5 ke Figure P3.3 10 Ω 2 k 6 kll 50 mA 10 kag 9 kng 18 kn 18 N 40 Ω (b) 5 V 100 Ωξ 25 Ω 22Ω3 600 0 2 kn 65 V 900 Ng 750 N3 500 ng $1.5 kn 3 kn (a) (c) 250 0 600 N 200 03 0.2 A(1) 300 g 150 Ω (d)
Transcribed Image Text:5 ke Figure P3.3 10 Ω 2 k 6 kll 50 mA 10 kag 9 kng 18 kn 18 N 40 Ω (b) 5 V 100 Ωξ 25 Ω 22Ω3 600 0 2 kn 65 V 900 Ng 750 N3 500 ng $1.5 kn 3 kn (a) (c) 250 0 600 N 200 03 0.2 A(1) 300 g 150 Ω (d)
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