(5) If two events A and B are mutually exclusive, then the joint events, AnC and BOC are also mutually exclusive and hence P((AUB)|C) = P(A|C)+ P(B\C)
(5) If two events A and B are mutually exclusive, then the joint events, AnC and BOC are also mutually exclusive and hence P((AUB)|C) = P(A|C)+ P(B\C)
Chapter8: Sequences, Series,and Probability
Section8.7: Probability
Problem 4ECP: Show that the probability of drawing a club at random from a standard deck of 52 playing cards is...
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