(5) If two events A and B are mutually exclusive, then the joint events, AnC and BOC are also mutually exclusive and hence P((AUB)|C) = P(A|C)+ P(B\C)

College Algebra
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ISBN:9781337282291
Author:Ron Larson
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Chapter8: Sequences, Series,and Probability
Section8.7: Probability
Problem 4ECP: Show that the probability of drawing a club at random from a standard deck of 52 playing cards is...
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Prove the property

(5)
If two events A and B are mutually exclusive, then the joint events, AnCand BnC
are also mutually exclusive and hence P((AUB)|C) = P(A\C)+P(B\C)
Transcribed Image Text:(5) If two events A and B are mutually exclusive, then the joint events, AnCand BnC are also mutually exclusive and hence P((AUB)|C) = P(A\C)+P(B\C)
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