-5 ƒ(x) = 3x + ½, find ƒ'(-5), using the definition of derivative. f'(-5) is the limit as of the expression ((3x+(5/x)-(-16)))/(x-(-5)) The value of this limit is Use this to find the equation of the tangent line to the graph of y = 3x + at the point (-5, -16) The equation of this tangent line can be written in the form y = (14/5)x-2

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