5- For the control system shown in Fig. 4, determine the steady state error for step input to 5, and for ramp with slope 10. (1,3,6] R(s) k s² + 5s +6 1 (s+1) C(s)

Power System Analysis and Design (MindTap Course List)
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ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter12: Power System Controls
Section: Chapter Questions
Problem 12.2P
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STEADY STATE ERROR (NEED A NEAT HANDWRITTEN SOLUTION ONLY OTHERWISE DOWNVOTE)

### Control System Steady State Error Analysis

**Problem Statement:**
For the control system shown in Figure 4, determine the steady-state error for a step input of 5 and for a ramp input with a slope of 10.

**System Description:**
The control system contains the following components:
1. A summing junction, taking \( R(s) \) as the input and producing the error signal.
2. A transfer function, \( \frac{k}{s^2 + 5s + 6} \), representing the system dynamics.
3. A feedback loop with a transfer function \( \frac{1}{s + 1} \).

**Figure 4:**
- **Input Signal \( R(s) \):** This is the initial input into the system.
- **Summing Junction:** This component adds the input signal \( R(s) \) and subtracts the feedback signal.
- **System Block:** Consists of the transfer function \( \frac{k}{s^2 + 5s + 6} \).
- **Output Signal \( C(s) \):** The output of the system before being fed back.
- **Feedback Loop:** The output passes through the transfer function \( \frac{1}{s + 1} \) and is fed back into the summing junction.

**Objective:**
- To calculate the steady-state error for a step input of magnitude 5.
- To calculate the steady-state error for a ramp input with a slope of 10.

---

To solve these problems, students will need to use concepts from control system theory such as steady-state error calculations, transfer function manipulation, and sensitivity functions. Detailed steps and assumptions must be provided to arrive at the solution for each type of input.

Reminder for Students:
- Review the final value theorem and apply it appropriately for both step and ramp inputs.
- Recall that steady-state error can be different for various types of inputs, depending on the type and order of the system.
Transcribed Image Text:### Control System Steady State Error Analysis **Problem Statement:** For the control system shown in Figure 4, determine the steady-state error for a step input of 5 and for a ramp input with a slope of 10. **System Description:** The control system contains the following components: 1. A summing junction, taking \( R(s) \) as the input and producing the error signal. 2. A transfer function, \( \frac{k}{s^2 + 5s + 6} \), representing the system dynamics. 3. A feedback loop with a transfer function \( \frac{1}{s + 1} \). **Figure 4:** - **Input Signal \( R(s) \):** This is the initial input into the system. - **Summing Junction:** This component adds the input signal \( R(s) \) and subtracts the feedback signal. - **System Block:** Consists of the transfer function \( \frac{k}{s^2 + 5s + 6} \). - **Output Signal \( C(s) \):** The output of the system before being fed back. - **Feedback Loop:** The output passes through the transfer function \( \frac{1}{s + 1} \) and is fed back into the summing junction. **Objective:** - To calculate the steady-state error for a step input of magnitude 5. - To calculate the steady-state error for a ramp input with a slope of 10. --- To solve these problems, students will need to use concepts from control system theory such as steady-state error calculations, transfer function manipulation, and sensitivity functions. Detailed steps and assumptions must be provided to arrive at the solution for each type of input. Reminder for Students: - Review the final value theorem and apply it appropriately for both step and ramp inputs. - Recall that steady-state error can be different for various types of inputs, depending on the type and order of the system.
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