5 def solveMaze ( maze ) : 6 # Creating a 5 *5 2-D list sol = [ [ 0 for j in range (5) ] for i in range (5) ] 7. 8. 9. if solveMazeUtil (maze, 0, 0, sol) == False: 1 print ("Solution doesn't exist"); return False 4 printSolution (sol) return True 7 # A recursive utility function to solve Maze problem 8 def solveMazeUtil (maze, x, y, sol) : # if (x, y is goal) return True if x == N - 1 and y == N - 1 and maze[x] [y] == 1: 1 2 sol [x] [y] = 1 return True 4 # Check if maze [x] [y] is valid if isSafe (maze, x, y) == True: # Check if the current block is already part of solution path. if sol[x] [y] = 1: 7

C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter15: Recursion
Section: Chapter Questions
Problem 12PE
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How this python code will look like in C++

25 def solveMaze ( maze ):
26
# Creating a 5 *
sol = [ [ 0 for j in range (5) ] for i in range (5) ]
27
5 2-D list
28
29
30
if solveMazeUtil (maze, 0, 0, sol)
== False:
31
print ("Solution doesn't exist");
32
return False
33
34
printSolution (sol)
35
return True
36
37 # A recursive utility function to solve Maze problem
38 def solveMazeUtil (maze, x, y, sol) :
39
# if (x, y is goal) return True
if x == N - 1 and y == N - 1 and maze [x] [y] == 1:
40
41
42
sol[x] [y]
= 1
43
return True
44
45
46
# Check if maze [x] [y] is valid
if isSafe (maze, x, y)
True:
# Check if the current block is already part of solution path.
if sol [x] [y] == 1:
47
48
49
return False
Transcribed Image Text:25 def solveMaze ( maze ): 26 # Creating a 5 * sol = [ [ 0 for j in range (5) ] for i in range (5) ] 27 5 2-D list 28 29 30 if solveMazeUtil (maze, 0, 0, sol) == False: 31 print ("Solution doesn't exist"); 32 return False 33 34 printSolution (sol) 35 return True 36 37 # A recursive utility function to solve Maze problem 38 def solveMazeUtil (maze, x, y, sol) : 39 # if (x, y is goal) return True if x == N - 1 and y == N - 1 and maze [x] [y] == 1: 40 41 42 sol[x] [y] = 1 43 return True 44 45 46 # Check if maze [x] [y] is valid if isSafe (maze, x, y) True: # Check if the current block is already part of solution path. if sol [x] [y] == 1: 47 48 49 return False
1 # Python3 program to solve Rat in a Maze
2 # problem using Recursion
3
4 # Maze size
5 N = 5
6.
7 # A utility function to print solution matrix sol
8 def printSolution ( sol ):
9.
10
for i in sol:
11
for j in i:
12
print (str(j) + " "
end ="")
13
print ("")
14
15 # A utility function to check if x, y is valid
16 # index for N * N Maze
17 def isSafe ( maze, x, y ) :
18
19
if x >= 0 and x < N and y >= 0 and y <N and maze[x] [y]
1:
==
20
return True
21
22
return False
23
24
Transcribed Image Text:1 # Python3 program to solve Rat in a Maze 2 # problem using Recursion 3 4 # Maze size 5 N = 5 6. 7 # A utility function to print solution matrix sol 8 def printSolution ( sol ): 9. 10 for i in sol: 11 for j in i: 12 print (str(j) + " " end ="") 13 print ("") 14 15 # A utility function to check if x, y is valid 16 # index for N * N Maze 17 def isSafe ( maze, x, y ) : 18 19 if x >= 0 and x < N and y >= 0 and y <N and maze[x] [y] 1: == 20 return True 21 22 return False 23 24
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