5- chapter31-question37 A square loop with length e = 1 m on each side is placed in a 5T uniform magnetic field pointing into the page. During a time interval t = 10 s, the loop is pulled from its two edges and turned into parallelogram, as shown. If the resistance is 10, find the induced current in the loop and its direction. Note: The area of parallelogram is: A = |7 x 1| = 1² sin 0. %3D Option1 Option2 Option3 2sin 0, Option4 Option5 (1- sin 0)/2, sin 0 /2, (1 + sin 0)/2, (1– sin 0)/2, clockwise clockwise Counterclockwise clockwise Counterclockwise a) O Option4 b) O Option1 c) O Option2 d) O Option3 e) O Option5 Boş bırak

Introductory Circuit Analysis (13th Edition)
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Author:Robert L. Boylestad
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5- chapter31-question37
A square loop with length e =1 m on each side is placed in a
5T uniform magnetic field pointing into the page. During a time
interval t = 10 s, the loop is pulled from its two edges and
turned into parallelogram, as shown. If the resistance is 10, find
the induced current in the loop and its direction. Note: The area
of parallelogram is: A = |7 × 1| = 1² sin 0.
Option1
(1– sin 0)/2,
Option2
Option3
Option4
Option5
sin 0 /2,
2sin 0,
(1+ sin 0)/2,
(1 – sin 0)/2,
clockwise
clockwise
Counterclockwise
clockwise
Counterclockwise
a)
Option4
b)
Option1
Option2
Option3
Option5
Boş bırak
Transcribed Image Text:5- chapter31-question37 A square loop with length e =1 m on each side is placed in a 5T uniform magnetic field pointing into the page. During a time interval t = 10 s, the loop is pulled from its two edges and turned into parallelogram, as shown. If the resistance is 10, find the induced current in the loop and its direction. Note: The area of parallelogram is: A = |7 × 1| = 1² sin 0. Option1 (1– sin 0)/2, Option2 Option3 Option4 Option5 sin 0 /2, 2sin 0, (1+ sin 0)/2, (1 – sin 0)/2, clockwise clockwise Counterclockwise clockwise Counterclockwise a) Option4 b) Option1 Option2 Option3 Option5 Boş bırak
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