5 As shown in the diagram below, quadrilateral DEFG is inscribed in a circle and mZD = 86. DK86° F

Elementary Geometry For College Students, 7e
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ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
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**Geometry Problem: Inscribed Quadrilateral**

**Problem Statement:**
As shown in the diagram below, quadrilateral \( DEFG \) is inscribed in a circle and \( m\angle D = 86^\circ \).

*(A diagram is included featuring a circle with four points labeled D, E, F, and G. These points form quadrilateral DEFG. The interior angle at point D is given as 86 degrees.)*

**Tasks:**
1. Determine and state \( m\angle GFE \).
2. Determine and state \( m\angle F \).

**Explanation:**

Given that quadrilateral \( DEFG \) is inscribed in a circle, we can use the property of an inscribed quadrilateral that states: opposite angles of an inscribed quadrilateral sum to \( 180^\circ \).

Therefore:
\[ m\angle D + m\angle F = 180^\circ \]

Since \( m\angle D = 86^\circ \):
\[ 86^\circ + m\angle F = 180^\circ \]
\[ m\angle F = 180^\circ - 86^\circ \]
\[ m\angle F = 94^\circ \]

Next, to determine \( m\angle GFE \), we observe that it is an external angle to triangle \(\Delta GFE\), thus:
\[ m\angle GFE = m\angle F\]

So,
\[ m\angle GFE = 94^\circ \]

**Conclusion:**
1. The measure of \( \angle GFE \) is \( 94^\circ \).
2. The measure of \( \angle F \) is \( 94^\circ \).
Transcribed Image Text:**Geometry Problem: Inscribed Quadrilateral** **Problem Statement:** As shown in the diagram below, quadrilateral \( DEFG \) is inscribed in a circle and \( m\angle D = 86^\circ \). *(A diagram is included featuring a circle with four points labeled D, E, F, and G. These points form quadrilateral DEFG. The interior angle at point D is given as 86 degrees.)* **Tasks:** 1. Determine and state \( m\angle GFE \). 2. Determine and state \( m\angle F \). **Explanation:** Given that quadrilateral \( DEFG \) is inscribed in a circle, we can use the property of an inscribed quadrilateral that states: opposite angles of an inscribed quadrilateral sum to \( 180^\circ \). Therefore: \[ m\angle D + m\angle F = 180^\circ \] Since \( m\angle D = 86^\circ \): \[ 86^\circ + m\angle F = 180^\circ \] \[ m\angle F = 180^\circ - 86^\circ \] \[ m\angle F = 94^\circ \] Next, to determine \( m\angle GFE \), we observe that it is an external angle to triangle \(\Delta GFE\), thus: \[ m\angle GFE = m\angle F\] So, \[ m\angle GFE = 94^\circ \] **Conclusion:** 1. The measure of \( \angle GFE \) is \( 94^\circ \). 2. The measure of \( \angle F \) is \( 94^\circ \).
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