5 & 6 I'm not able to understandPl 1.Find the exact step counts (growth function) and time complexity for following algorithms -iii.Algorithm Add(a,b,c,m,n)1. for i:=1to m do2.for i:=1 to n do3.i.1. Input m and n2. If m == n3.4.5.Print "Same"Sum=m+nPrint Sum6.Else Print "Not same"iv.1. int i, j, k = 0;2.for (i = 1; i <= n*n; i++)3.4.5.6.vii.1. Set i=02. Repeat step 3-6 till i<=n3.Set J-n4.While J>0i=i+1ii.1. Initialize i=0for (j = 1; j <= n; j =j+1)k = k + n/2;J=J/22. For i=0 to n-13.4. For i=0 to n-15.Read an integer in Arr[i]Print Arr[i]V.Algorithm Sum (a,n)1 s:=0.0;234 return s;for i:=1 to n doviii.1. Set In2. While I>13.4.5.6.7.8.9.While J

Steps count - Total steps taken to get the final result. Time complexity: Time is taken by an…

Answered: 5 & 6 I'm not able to understand Pl

Engineering

Computer Science

5 & 6 I'm not able to understand Pl

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Concept explainers

Concept of Pointer Parameter

Pointers are the special variable that stores the variable address, instead of storing the variable value. Pointer is a powerful feature of a programming language. A pointer is mostly used to save memory space and improve execution time.

Question

5 & 6 I'm not able to understand

1.Find the exact step counts (growth function) and time complexity for following algorithms -
iii.
Algorithm Add(a,b,c,m,n)
1. for i:=1to m do
2.
for i:=1 to n do
3.
i.
1. Input m and n
2. If m == n
3.
4.
5.
Print "Same"
Sum=m+n
Print Sum
6.Else Print "Not same"
iv.
1. int i, j, k = 0;
2.for (i = 1; i <= n*n; i++)
3.
4.
5.
6.
vii.
1. Set i=0
2. Repeat step 3-6 till i<=n
3.
Set J-n
4.
While J>0
i=i+1
ii.
1. Initialize i=0
for (j = 1; j <= n; j =j+1)
k = k + n/2;
J=J/2
2. For i=0 to n-1
3.
4. For i=0 to n-1
5.
Read an integer in Arr[i]
Print Arr[i]
V.
Algorithm Sum (a,n)
1 s:=0.0;
2
3
4 return s;
for i:=1 to n do
viii.
1. Set In
2. While I>1
3.
4.
5.
6.
7.
8.
9.
While J <n
I/= 2
s :=s+a[i];
K=1
While K<n
J*= 2
K+=2
ix.
c[i,j]:=a[i, j]+b[i,j];
vi.
1. sum 0
2. for i=1 to n:
3.
4.
for j = i to n:
5.print(sum)
1. {
2.
3.
4.
5.
6. }
sum += a[i][j]
void fun(int n, int arr[])
int i = 0, j = 0;
for(; i<n; ++i)
while(j<n && arr[i]<arr[j])
j+t:

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