5) Air, initially at 373 K , 1 atm , and V,=1 liter undergoes two successive reversible expansions -a reversible isothermal expansion to some intermediate volume V, , followed by a reversible adiabatic expansion to a final volume V, , cooling the gas to final temperature of 273 K. Calculate V,, V,,Q, and W, for the process. Assume ideal gas behavior.
5) Air, initially at 373 K , 1 atm , and V,=1 liter undergoes two successive reversible expansions -a reversible isothermal expansion to some intermediate volume V, , followed by a reversible adiabatic expansion to a final volume V, , cooling the gas to final temperature of 273 K. Calculate V,, V,,Q, and W, for the process. Assume ideal gas behavior.
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Take V2 final volume to be 3 liters.
![5) Air, initially at 373 K , 1 atm , and V, = 1 liter undergoes two successive reversible expansions –a
reversible isothermal expansion to some intermediate volume V, , followed by a reversible adiabatic
expansion to a final volume V, , cooling the gas to final temperature of 273 K. Calculate V,, V,,Q, and
W, for the process. Assume ideal gas behavior.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8558e3bd-f6b8-4bf1-9e6c-c3eb0cee7f41%2Fb60a1527-7f05-4e48-90ae-fae576044c3b%2Fbku9mr6_processed.png&w=3840&q=75)
Transcribed Image Text:5) Air, initially at 373 K , 1 atm , and V, = 1 liter undergoes two successive reversible expansions –a
reversible isothermal expansion to some intermediate volume V, , followed by a reversible adiabatic
expansion to a final volume V, , cooling the gas to final temperature of 273 K. Calculate V,, V,,Q, and
W, for the process. Assume ideal gas behavior.
Expert Solution
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Step 1
Gamma of air is 1.4.
As the first process is isothermal in nature, the temperature of the air remains constant. This, we have :
For the adiabatic process, we have :
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