(5) A student used "U-substitution" 3 integral: S x² √√9- x² dx By using the following steps: Let U = 9-x² du = -2x dx - du 2xdx x² =√19-u substituting following ←つ answer: = 9-x² : =-12/20 · =√ S 2 - on the du √x.x²³ √ 9-x²³ dx X = S-² (9-~) u ²² 3/2 1/2 90²² - 0² qu du du After integrating and the student got the | 1 (9-x²15¹/²2 -3 (9-x² √²¹/²2 + c)

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