I need help ### Problem Statement:A solution is made by combining 75.0 mL of 0.0040 M Na₂SO₄ and 25.0 mL of 0.080 M AgNO₃. Calculate the final concentrations of all four ions in solution. The \( K_{sp} \) of Ag₂SO₄ is \( 1.5 \times 10^{-5} \).### Solution Steps:1. **Volume and Mol Calculations:** We have: - 75.0 mL of 0.0040 M Na₂SO₄ - 25.0 mL of 0.080 M AgNO₃ - Final total volume = 100 mL2. **Concentration Adjustments for Dilution:** For Na₂SO₄: \[ C_1 = 0.0040 \, \text{M} \] \[ V_1 = 75 \, \text{mL} \] \[ V_f = 100 \, \text{mL} \] \[ C_f (Na₂SO₄) = C_1 \times \frac{V_1}{V_f} = 0.0040 \times \frac{75}{100} = 0.0030 \, \text{M} \] Splitting into ions: \[ Na₂SO₄ \rightarrow 2Na^+ + SO₄^{2-} \] \[ SO₄^{2-} = 0.0030 \, \text{M} \] \[ Na^+ = 2 \times 0.0030 \, \text{M} = 0.0060 \, \text{M} \] For AgNO₃: \[ C_3 = 0.080 \, \text{M} \] \[ V_3 = 25 \, \text{mL} \] \[ V_f = 100 \, \text{mL} \] \[ C_f (AgNO₃) = C_3 \times \frac{V_3}{V_f} = 0.080 \times \frac{25}{100} = 0.020 \, \text{

Volume of Na2SO4 solution = 75 mLConcentration of Na2SO4 solution = 0.004 MVolume of AgNO3 solution…

5) A solution is made by combining 75.0 mL of 0.0040 M Na2SO4 and 25.0 mL of 0.080 M AgNO3. Calculate the final concentrations of all four ions in solution. The Ksp of Ag2SO4 is 1.5 x 10-5. 75,0ML Na₂ soy 2 50ml. 1002

5) A solution is made by combining 75.0 mL of 0.0040 M Na2SO4 and 25.0 mL of 0.080 M AgNO3. Calculate the final concentrations of all four ions in solution. The Ksp of Ag2SO4 is 1.5 x 10-5. 75,0ML Na₂ soy 2 50ml. 1002

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Chapter8: Polyfunctional Acids And Bases

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Question

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### Problem Statement:
A solution is made by combining 75.0 mL of 0.0040 M Na₂SO₄ and 25.0 mL of 0.080 M AgNO₃. Calculate the final concentrations of all four ions in solution. The \( K_{sp} \) of Ag₂SO₄ is \( 1.5 \times 10^{-5} \).

### Solution Steps:

1. **Volume and Mol Calculations:**
We have:
- 75.0 mL of 0.0040 M Na₂SO₄
- 25.0 mL of 0.080 M AgNO₃
- Final total volume = 100 mL

2. **Concentration Adjustments for Dilution:**
For Na₂SO₄:
\[ C_1 = 0.0040 \, \text{M} \]
\[ V_1 = 75 \, \text{mL} \]
\[ V_f = 100 \, \text{mL} \]
\[ C_f (Na₂SO₄) = C_1 \times \frac{V_1}{V_f} = 0.0040 \times \frac{75}{100} = 0.0030 \, \text{M} \]

Splitting into ions:
\[ Na₂SO₄ \rightarrow 2Na^+ + SO₄^{2-} \]
\[ SO₄^{2-} = 0.0030 \, \text{M} \]
\[ Na^+ = 2 \times 0.0030 \, \text{M} = 0.0060 \, \text{M} \]

For AgNO₃:
\[ C_3 = 0.080 \, \text{M} \]
\[ V_3 = 25 \, \text{mL} \]
\[ V_f = 100 \, \text{mL} \]
\[ C_f (AgNO₃) = C_3 \times \frac{V_3}{V_f} = 0.080 \times \frac{25}{100} = 0.020 \, \text{

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