Projectile Motion. **Problem 5:**A baby falls from the top of a 45 m building. What is the minimum speed that Spiderman must push off from the same building one second later in order to catch the baby before she strikes the ground?**Explanation:**Given:- Height of the building (h) = 45 meters- Gravity (g) = 9.8 m/s²- Delay time for Spiderman's push-off (t_delay) = 1 secondTo find: The minimum speed Spiderman must use to push off (v_spiderman).1. **Calculate the time taken for the baby to reach the ground**: Use the formula for distance under constant acceleration: \[ h = \frac{1}{2} g t^2 \] Rearranging to solve for time (t): \[ t = \sqrt{\frac{2h}{g}} \] Plugging in the values: \[ t = \sqrt{\frac{2 \times 45}{9.8}} \approx 3.03 \, \text{seconds} \]2. **Time available for Spiderman to catch the baby**: Since Spiderman delays by 1 second, the time available for him to catch the baby: \[ t_{available} = t - t_{delay} = 3.03 \, \text{seconds} - 1 \, \text{second} = 2.03 \, \text{seconds} \]3. **Calculate Spiderman's minimum speed**: Use the formula for speed: \[ v = \frac{d}{t} \] Where distance (d) = height from which the baby falls = 45 meters, and time (t) = time available for Spiderman = 2.03 seconds: \[ v_{spiderman} = \frac{45}{2.03} \approx 22.17 \, \text{m/s} \]Therefore, Spiderman must push off with a minimum speed of approximately 22.17 meters per second to catch the baby before she strikes the ground.

Name: Projectile Motion. **Problem 5:**A baby falls from the top of a 45 m b
Uploaded: 2024-03-20T06:57:47.000Z
Channel: Bartleby
Description: Projectile Motion. **Problem 5:**A baby falls from the top of a 45 m building. What is the minimum speed that Spiderman must push off from the same building one second later in order to catch the baby before she strikes the ground?**Explanation:**Giv