^ ( √5 )₁ + ( 75 ) 1 15 S Show that the directional derivative of f(x, y, z) = z²x + y3 at (3, 9, 2) in the direction To find the directional derivative of f, we first need the gradient of fat (3, 9, 2). This is equal to '( √5)² . Therefore, the directional derivative of f(x, y, z) = z²x + y3 in the direction of jis 98√5. i+ 2 Next, we take the ---Select--- jis 98√5. ² (→ √ 5 ) ₁ + ( √²/5) ³. - j. This product is of this vector and the vector
^ ( √5 )₁ + ( 75 ) 1 15 S Show that the directional derivative of f(x, y, z) = z²x + y3 at (3, 9, 2) in the direction To find the directional derivative of f, we first need the gradient of fat (3, 9, 2). This is equal to '( √5)² . Therefore, the directional derivative of f(x, y, z) = z²x + y3 in the direction of jis 98√5. i+ 2 Next, we take the ---Select--- jis 98√5. ² (→ √ 5 ) ₁ + ( √²/5) ³. - j. This product is of this vector and the vector
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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2
Show that the directional derivative of f(x, y, z) = z²x + y³ at (3, 9, 2) in the direction ( √5) ₁ + (75) ₁ is
is 98√/5.
To find the directional derivative of f, we first need the gradient of fat (3, 9, 2). This is equal to
Therefore, the directional derivative of f(x, y, z) = z²x + y³ in the direction of
. Next, we take the ---Select---
1
2
( √5)i + (7/5)³ is
is 98√/5.
1
2
( √5)² + (²/5)
i
of this vector and the vector
j. This product is
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