5) 5e3x+4 15
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
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![**Problem 5**
Solve the exponential equation:
\[ 5e^{3x + 4} = 15 \]
Steps to solve:
1. Begin by isolating the exponential term. Divide both sides of the equation by 5:
\[ e^{3x + 4} = 3 \]
2. Apply the natural logarithm (ln) to both sides to eliminate the base \(e\):
\[ \ln(e^{3x + 4}) = \ln(3) \]
3. Use the logarithm property \( \ln(a^b) = b\ln(a) \):
\[ 3x + 4 = \ln(3) \]
4. Isolate the variable \(x\). Subtract 4 from both sides:
\[ 3x = \ln(3) - 4 \]
5. Finally, divide by 3 to solve for \(x\):
\[ x = \frac{\ln(3) - 4}{3} \]
Therefore, the solution to the equation is:
\[ x = \frac{\ln(3) - 4}{3} \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffbfc9c6a-8538-4a72-a7a3-8a03419f890c%2Fb31290d6-2f03-44d3-8921-6af63d0f782a%2Fb7ynnu5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem 5**
Solve the exponential equation:
\[ 5e^{3x + 4} = 15 \]
Steps to solve:
1. Begin by isolating the exponential term. Divide both sides of the equation by 5:
\[ e^{3x + 4} = 3 \]
2. Apply the natural logarithm (ln) to both sides to eliminate the base \(e\):
\[ \ln(e^{3x + 4}) = \ln(3) \]
3. Use the logarithm property \( \ln(a^b) = b\ln(a) \):
\[ 3x + 4 = \ln(3) \]
4. Isolate the variable \(x\). Subtract 4 from both sides:
\[ 3x = \ln(3) - 4 \]
5. Finally, divide by 3 to solve for \(x\):
\[ x = \frac{\ln(3) - 4}{3} \]
Therefore, the solution to the equation is:
\[ x = \frac{\ln(3) - 4}{3} \]
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