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5-5. The cable supports the loading shown. Determine the magnitude of the horizontal force P so that x = 6 ft. B' 5 ft P C| 8 ft 400 lb D| 2 ft 2 ft A 十

5-5. The cable supports the loading shown. Determine the magnitude of the horizontal force P so that x = 6 ft. B' 5 ft P C| 8 ft 400 lb D| 2 ft 2 ft A 十

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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**Problem 5-5: Cable Support System** The diagram illustrates a cable support system subjected to a loading. The objective is to determine the magnitude of the horizontal force \( P \) needed to maintain equilibrium when the horizontal distance \( x \) is 6 feet. **Diagram Explanation:** - A cable is shown supporting a force, with points labeled \( A \), \( B \), \( C \), and \( D \). - The cable starts at point \( A \), moves vertically to point \( B \), and runs horizontally to point \( C \). From point \( C \), it then extends diagonally to point \( D \), where a 400 lb horizontal force is applied. - The vertical distance from \( A \) to \( B \) is 5 ft. - The horizontal distance from \( A \) to \( D \) is 2 ft. - The horizontal distance from \( C \) to the wall (point \( B \)) is variable \( x \), specified to be 6 ft in this problem. - The vertical distance from \( B \) to \( C \) is 8 ft. - The diagram includes a static force applied at point \( D \). **Objective:** To determine the magnitude of the horizontal force \( P \) necessary to keep the system in equilibrium with \( x = 6 \) ft. This requires analyzing the static equilibrium of the system, considering forces and distances provided in this setup.
Transcribed Image Text:**Problem 5-5: Cable Support System** The diagram illustrates a cable support system subjected to a loading. The objective is to determine the magnitude of the horizontal force \( P \) needed to maintain equilibrium when the horizontal distance \( x \) is 6 feet. **Diagram Explanation:** - A cable is shown supporting a force, with points labeled \( A \), \( B \), \( C \), and \( D \). - The cable starts at point \( A \), moves vertically to point \( B \), and runs horizontally to point \( C \). From point \( C \), it then extends diagonally to point \( D \), where a 400 lb horizontal force is applied. - The vertical distance from \( A \) to \( B \) is 5 ft. - The horizontal distance from \( A \) to \( D \) is 2 ft. - The horizontal distance from \( C \) to the wall (point \( B \)) is variable \( x \), specified to be 6 ft in this problem. - The vertical distance from \( B \) to \( C \) is 8 ft. - The diagram includes a static force applied at point \( D \). **Objective:** To determine the magnitude of the horizontal force \( P \) necessary to keep the system in equilibrium with \( x = 6 \) ft. This requires analyzing the static equilibrium of the system, considering forces and distances provided in this setup.
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