5-5. The 25-kg bar has a center of mass at G. If it is upported by a smooth peg at C, a roller at A, and cord AB, letermine the reactions at these supports. 0.3 m D 0.2 m B 0.5 m 30° |15 Prob. F5-5

Q: "601 Problem #1: Use Method of Joints | 600E(lb) E B (Ib) · A 30 B -3 ft- 3 ft 1. Determine the…

A:

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Q: Wi 15 ш P2 P2 P₁ P₂ ші ш

A: Given: To find: Shear and moment

Q: 2. Determine the reactions in the supports and draw the shear diagram.statb mSTgeib 18odz orlt mi…

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Q: F: ( Select) G: ( Select) 20 N 40 N 40 N 20 N F D 2 m H. E G 10 m KOOL Mo No- 4 m 4 m 4 m 2m 2m

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A: Given : To Find : Determine the support reaction ?

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Q: Determine support reaction at A and B

A: Apply equilibrium : ∑FX=0∑FY=0∑M=0

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Q: - DETERMINE FORCES IN ALL MEMBERS IndiCATE WETHER FENSION I OR T COMPRESSION Гом A B 10m 30° гом So…

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Q: 5. Determine the reactions at the supports in the portal frame shown. Given: E-constant for all…

A: given Data: PL = 12kn and 30kn Need to find VA and HA

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A: Solution Weight, W = 40 kg                   = 40×9.81 = 392.4 N Tension in the cable, T = r ^ |T|…

Q: 3. Determine the support reactions in the beams 40 kips B 8 kips B 4' 10+ 10 w = 4 kips/ft 4 10' w =…

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Q: Determine the member force on member IJ.

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Q: he to The structure loaded as shuwn : he 4m P 40 KN E 200 GPa 12=1c_100 x 10° mm • Solve the…

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Q: *4-12 The truss is made of three A-36 steel members, each having a cross-sectional area of 400 mm².…

A: Sc= 0.0975 mmExplanation:

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Q: Roller at A and pins at C and E. 18EN 4 KN/m -2m-

A: Degree of static indeterminacy -  Ds = re - 3 - rr here, re = Total reactions = 4 ( 3 of fixed…

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A: please find the attached solution below.

Q: Sec. 9.1-9.4 9-1. Determine the reactions at the supports, then draw the moment diagram. El is…

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Q: The compound beam is pin supported at C and supported by a roller at A and B. There is a hinge (pin)…

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Q: Determine the forces in members GF and GC.  F1 = 21 kN F2 = 29 kN F3 = 25 kN

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Q: Find the force in the member BC * 4 kN 2 kN By C 60° A 60% 60° 60° D E ARD 3 m 3 m RAF

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Q: EX/Determine the reaction at the support.Assume Ais Fixed B and c is rod = = FTITIT 4m 4m 2KW B ↓ 2m…

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Q: 20KN/m P2=40とN A=70° um メ 1- Find the support reactions of the simple beam 2- Fnd internal force…

A: Fy=0Va+Vb=150sin70°+80×7+20×1.5+70= 796.95 KN Mb=0Va×7-20×1.5×7.75-80×3.5×7-150×sin70°+70×2=0…

Q: Calculate the reactions at the hinge support at B. Skip 7 kip 10 kip 2 kip -as kip 6 ft

A:

Laws of Equilibrium

A body is said to be in equilibrium if the system of forces acting on the body tends to keep the body at rest, in other words, there is no translation motion or net torque on the body. Under such conditions, the equilibrium conditions are to be applied to analyze the condition. The branch of mechanics that deals with this condition is known as 'statics'. Under equilibrium, there are no net forces on the body.