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5- 4 3 2 +H 1 bat -3 -4 2 V = 4 5 6 8 ( The graph above shows the base of an object. Compute the value of the volume of the object, given that cross sections (perpendicular to the base) are squares. Give an exact expression or round your answer to at least two decimals.

5- 4 3 2 +H 1 bat -3 -4 2 V = 4 5 6 8 ( The graph above shows the base of an object. Compute the value of the volume of the object, given that cross sections (perpendicular to the base) are squares. Give an exact expression or round your answer to at least two decimals.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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U 5 4 3 2 1 -2 -3 -4 6 V = 8 ( The graph above shows the base of an object. Compute the value of the volume of the object, given that cross sections (perpendicular to the base) are squares. Give an exact expression or round your answer to at least two decimals.
Transcribed Image Text:U 5 4 3 2 1 -2 -3 -4 6 V = 8 ( The graph above shows the base of an object. Compute the value of the volume of the object, given that cross sections (perpendicular to the base) are squares. Give an exact expression or round your answer to at least two decimals.
Expert Solution
Step 1: Description of given data
For x equals 0 rightwards arrow x equals 6
Side of square is S equals y equals 4 over 6 x minus left parenthesis negative 4 over 6 x right parenthesis equals bold 4 over bold 3 bold italic x
Area of square will be, A left parenthesis x right parenthesis equals open parentheses 4 over 3 x close parentheses squared equals bold 16 over bold 9 bold italic x to the power of bold 2
For x equals 6 space rightwards arrow space x equals 7
Side of square is, S equals 6 minus open parentheses negative 6 close parentheses equals bold 12
Area of square will be, A left parenthesis x right parenthesis equals open parentheses 12 close parentheses squared equals bold 144

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