5 4 3 2 1 -1 -2 -3- J/2 37/2 -st Q The graph of the function y = secx is given above for the interval x = [0, 2π] ONLY. Answer the questions below based on the interval x = [0, 2π] ONLY. Use EXACT answers and interval notation where appropriate. The local maximum of y = sec x on this interval is at x = The function y = secx is positive for a E The vertical asymptotes of y = sec x on this interval are at x = separated by commas.) The function y = secx is increasing for a E + 2 The function y = sec x is concave down for x E Question Help: Message instructor Post to forum (List them (Interval notation for the next three ...)

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