5 + 3-j4 2 10 L90° V 12 + + 15/0% V 200° Za = 5 ohms Zb= 3-j4 ohms Zc= 2 ohms Zd = 12 ohms V1= 20 angle 0 V2 = 10 angle 90 V3 = 15 angle 0 1. Same figure, solve the node voltages and branch currents using Nodal theorem.
5 + 3-j4 2 10 L90° V 12 + + 15/0% V 200° Za = 5 ohms Zb= 3-j4 ohms Zc= 2 ohms Zd = 12 ohms V1= 20 angle 0 V2 = 10 angle 90 V3 = 15 angle 0 1. Same figure, solve the node voltages and branch currents using Nodal theorem.
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question
Nodal

Transcribed Image Text:5
+
3-j4
20/0°
2
10/90°
12
+
15 L00
V
V
+
Za = 5 ohms
Zb= 3-j4 ohms
Zc= 2 ohms
Zd = 12 ohms
V1= 20 angle 0
V2 = 10 angle 90
V3 = 15 angle 0
1.
Same figure, solve the node voltages and branch
currents using Nodal theorem.
Solve neatly and correctly. Round off your solutions to 3
decimal places. Box your final answers.
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