5) 15.3 grams of Lithium is dropped into a solution containing excess copper II phosphate. When the reaction is completed, 1.25 grams of copper is formed. What is the percent yield?
5) 15.3 grams of Lithium is dropped into a solution containing excess copper II phosphate. When the reaction is completed, 1.25 grams of copper is formed. What is the percent yield?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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How would you solve number 5?
![Legnation UR ts .cd
The s
ttht can be foeed f given reatants
reactonts
Acal X -The of product
that ay foems when the reaction is carried out in the tah
Dactors the atal amount witi ALWAYS be less than the theoretieal yield
as much as we anticipate, this Factual" amount from the lab esperiment
ariety
real h we
Eexnt eM-The rante of the actual sield to the theuretical.vield expressed as a percentage.
Pereat Ye
Actual
Theeretical
100
EXAMPLE How many grams of hvdrofluorie acid (HF) are required to react completely with 23.66
grams of calcium hydroxide in the foliowing reaction?
1 Ca(OH),+
2 mol HF
2 HF>
1 CaF+ 2 H0
-G.535Cn
Theoretioal Yie
I mol Ca(OH):
---- x --
20.01 g HF
23.68 g Ca(OH): X-
= 12.79 g. AE)
1 mol Ca(OH):
Based on the stoichiometry of this problem, the Theoretical Yield for this problem is 12.79 g HF But,
when this experiment was conducted, an Actual Yield of only 10.41 g HF was collected. Using the
74.10 g Ca(OH):
1 mol HF
equation for percent yield, the Percent Yield of this experiment was 81.39%.
10.41g HF, x 100 - 81.39%
Percent Yield-
Actual
Theoretical
x 100 -
12.79g HF
1)A student adds 200.0g of CrHeO3 to an excess of CAHOO3, this produces CsH8O4 and
C2H4O2. Calculate the percent yield if 231 g of aspirin (CoHeO4) is produced in an experiment.
CrHeO3 +_ CaHeO3 →_C»H®O4 + _] C2H4O2
2) According to the following equation, Calculate the percentage yield if 550.0 g of toluene
(C;Hs )added to an excess of nitric acid (HNO,) provides 305 g of the p-nitrotoluene (CH;NO2 )
product in a lab experiment.
C7H8 +_ HNO3 → _ C7H7NO2 +_H2O
3 Aluminum reacts with an aqueous solution containing excess copper (II) sulfate. If 1.85 g AI
reacts and the percentage yield of Cu is 56.6%, what mass of Cu is produced?
2AI +3CuSO4 →__Cu +Al2(SO4)3
4) The combustion of methane(CH4) produces carbon dioxide and water. Assume that 2.0 mol
of CH4 burned in the presence of excess air. What is the percentage yield if in an experiment
the reaction produces 87.0 g of CO2?
5) 15.3 grams of Lithium is dropped into a solution containing excess copper II phosphate.
When the reaction is completed, 1.25 grams of copper is formed. What is the percent yield?
DO NOT WRITE ON THIS SHEET](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2b8424d5-ae98-44ad-9944-722de3538f6e%2Fe877a838-cfc0-4d41-8592-0a22e6325826%2Fdb3ufad_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Legnation UR ts .cd
The s
ttht can be foeed f given reatants
reactonts
Acal X -The of product
that ay foems when the reaction is carried out in the tah
Dactors the atal amount witi ALWAYS be less than the theoretieal yield
as much as we anticipate, this Factual" amount from the lab esperiment
ariety
real h we
Eexnt eM-The rante of the actual sield to the theuretical.vield expressed as a percentage.
Pereat Ye
Actual
Theeretical
100
EXAMPLE How many grams of hvdrofluorie acid (HF) are required to react completely with 23.66
grams of calcium hydroxide in the foliowing reaction?
1 Ca(OH),+
2 mol HF
2 HF>
1 CaF+ 2 H0
-G.535Cn
Theoretioal Yie
I mol Ca(OH):
---- x --
20.01 g HF
23.68 g Ca(OH): X-
= 12.79 g. AE)
1 mol Ca(OH):
Based on the stoichiometry of this problem, the Theoretical Yield for this problem is 12.79 g HF But,
when this experiment was conducted, an Actual Yield of only 10.41 g HF was collected. Using the
74.10 g Ca(OH):
1 mol HF
equation for percent yield, the Percent Yield of this experiment was 81.39%.
10.41g HF, x 100 - 81.39%
Percent Yield-
Actual
Theoretical
x 100 -
12.79g HF
1)A student adds 200.0g of CrHeO3 to an excess of CAHOO3, this produces CsH8O4 and
C2H4O2. Calculate the percent yield if 231 g of aspirin (CoHeO4) is produced in an experiment.
CrHeO3 +_ CaHeO3 →_C»H®O4 + _] C2H4O2
2) According to the following equation, Calculate the percentage yield if 550.0 g of toluene
(C;Hs )added to an excess of nitric acid (HNO,) provides 305 g of the p-nitrotoluene (CH;NO2 )
product in a lab experiment.
C7H8 +_ HNO3 → _ C7H7NO2 +_H2O
3 Aluminum reacts with an aqueous solution containing excess copper (II) sulfate. If 1.85 g AI
reacts and the percentage yield of Cu is 56.6%, what mass of Cu is produced?
2AI +3CuSO4 →__Cu +Al2(SO4)3
4) The combustion of methane(CH4) produces carbon dioxide and water. Assume that 2.0 mol
of CH4 burned in the presence of excess air. What is the percentage yield if in an experiment
the reaction produces 87.0 g of CO2?
5) 15.3 grams of Lithium is dropped into a solution containing excess copper II phosphate.
When the reaction is completed, 1.25 grams of copper is formed. What is the percent yield?
DO NOT WRITE ON THIS SHEET
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