Suppose a government organization reported the accompanying data on the number of speed-related crash fatalities during holiday periods for the years from 1994 to 2003.Speed-Related FatalitiesYearNew Years DayMemorial DayJuly 4thLabor DayThanksgivingChristmas19941471971781932121521995148174219188198129199617618520216621866199776197179179210183199821913816916220313419991381831781711681912000171156219180187155200113419064138217210200221018823420221060200370181184189202198n USE SALT(а)Calculate the standard deviation for the New Year's Day data. (Round the answer to four decimal places.)(b)Day data.Without calculating the standard deviation of the Memorial Day data, determine whether the standard deviation for the Memorial Day data would be larger or smaller than the standard deviation of the New Year'slargero smaller(c)week every year. Based on the given data, is there more or less variability in the speed-related crash fatality numbers from year to year for same day of the week holiday periods than for holidays that can occuron different days of the week? Support your answer with appropriate measures of variability. (Round your answers to four decimal places.)Memorial Day and Labor Day are holidays that always occur on Monday and Thanksgiving always occurs on a Thursday, whereas New Year's Day, July 4th, and Christmas do not always fall on the same day of theThe standard deviations for Memorial Day, Labor Day, and Thanksgiving areandrespectively. The standard deviations for New Year's Day, July 4th, and Christmasareand, respectively. The standard deviations for the same day of the week holidays are all smallerthan all of the standard deviations for the holidaysthat can occur on different days of the week. There is ( lessvariability for the holidays that always occur on the same day of the week.

Answered: 5 148 174 219 188 198 129 176 185 202…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose a government organization reported the accompanying data on the number of speed-related crash fatalities during holiday periods for the years from 1994 to 2003.
Speed-Related Fatalities
Year
New Years Day
Memorial Day
July 4th
Labor Day
Thanksgiving
Christmas
1994
147
197
178
193
212
152
1995
148
174
219
188
198
129
1996
176
185
202
166
218
66
1997
76
197
179
179
210
183
1998
219
138
169
162
203
134
1999
138
183
178
171
168
191
2000
171
156
219
180
187
155
2001
134
190
64
138
217
210
2002
210
188
234
202
210
60
2003
70
181
184
189
202
198
n USE SALT
(а)
Calculate the standard deviation for the New Year's Day data. (Round the answer to four decimal places.)
(b)
Day data.
Without calculating the standard deviation of the Memorial Day data, determine whether the standard deviation for the Memorial Day data would be larger or smaller than the standard deviation of the New Year's
larger
o smaller
(c)
week every year. Based on the given data, is there more or less variability in the speed-related crash fatality numbers from year to year for same day of the week holiday periods than for holidays that can occur
on different days of the week? Support your answer with appropriate measures of variability. (Round your answers to four decimal places.)
Memorial Day and Labor Day are holidays that always occur on Monday and Thanksgiving always occurs on a Thursday, whereas New Year's Day, July 4th, and Christmas do not always fall on the same day of the
The standard deviations for Memorial Day, Labor Day, and Thanksgiving are
and
respectively. The standard deviations for New Year's Day, July 4th, and Christmas
are
and
, respectively. The standard deviations for the same day of the week holidays are all smaller
than all of the standard deviations for the holidays
that can occur on different days of the week. There is ( less
variability for the holidays that always occur on the same day of the week.

Expert Solution

Step 1

a).

For the calculation of standard deviation, we will first need to find the mean

The following table shows the required calculations.

Observation:	$X$	$X^2$
1	147	21609
2	148	21904
3	176	30976
4	76	5776
5	219	47961
6	138	19044
7	171	29241
8	134	17956
9	210	44100
10	70	4900
Sum =	$1489$	$243467$

The formula and calculation for mean is shown as follows;

$M e a n = \frac{\sum_{} x_{i}}{n} = \frac{147 + . . . . . + 70}{10} = \frac{1489}{10} = 148.9$

The formula and calculations for the standard deviation is shown as follows;

$S \tan d a r d d e v i t a i o n = \sqrt{\frac{1}{n - 1} \sum_{i = 1}^{n} {(x_{i} - \bar{x})}^{2}} = \sqrt{\frac{{(147 - 148.9)}^{2} + . . . . + {(70 - 148.9)}^{2}}{10 - 1}} = \sqrt{\frac{21754.9}{9}} = \sqrt{2417.2111111111} = 49.165141219274 \approx 49.1651$