:5 1.5116 1.2596 =7 1.0077 0.8566 50 0.7558 75 0.5039 0.3779 25 0.3023 50 0.2519 75 0.2159 D0 0.1889 erage rate of this reaction between 5.25 min. and 7.87 min.: (M/min) = humber (rtol=D0.03, atol=1e-08) e x0%
:5 1.5116 1.2596 =7 1.0077 0.8566 50 0.7558 75 0.5039 0.3779 25 0.3023 50 0.2519 75 0.2159 D0 0.1889 erage rate of this reaction between 5.25 min. and 7.87 min.: (M/min) = humber (rtol=D0.03, atol=1e-08) e x0%
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![The tabulated data were collected for this reaction at 322 K:
A(9) → B(9)
Тime(min.)
[A] (M)
5.25
1.5116
6.30
1.2596
7.87
1.0077
9.26
0.8566
10.50
0.7558
15.75
0.5039
21.00
0.3779
26.25
0.3023
31.50
0.2519
36.75
0.2159
42.00
0.1889
Determine the average rate of this reaction between 5.25 min. and 7.87 min.:
average rate(M/min)
humber (rtol=0.03, atol=1e-08)
e x 0%](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F63cfaafd-139a-4867-be13-27869dc799da%2F1aae06ac-2f27-4916-b8b8-5f006c0ac61b%2Fkgbr3k_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The tabulated data were collected for this reaction at 322 K:
A(9) → B(9)
Тime(min.)
[A] (M)
5.25
1.5116
6.30
1.2596
7.87
1.0077
9.26
0.8566
10.50
0.7558
15.75
0.5039
21.00
0.3779
26.25
0.3023
31.50
0.2519
36.75
0.2159
42.00
0.1889
Determine the average rate of this reaction between 5.25 min. and 7.87 min.:
average rate(M/min)
humber (rtol=0.03, atol=1e-08)
e x 0%
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