4ytt = yxx, 0 < x < π, t> 0; y(0, 1) y(x,0)=yt (x,0) = sinx y (л, t) 0,

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter6: Applications Of The Derivative
Section6.CR: Chapter 6 Review
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Help with this boundary value problem

3. 4ytt = Yxx, 0 < x <
y(x,0) = y(x,0) =
, t > 0; y(0,t) = y(л,t) = 0,
sin x
Transcribed Image Text:3. 4ytt = Yxx, 0 < x < y(x,0) = y(x,0) = , t > 0; y(0,t) = y(л,t) = 0, sin x
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