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(4y-1) F. 7x+2 9. Find AB. B. 12y A 10. Find mzABC. the rhombus.

(4y-1) F. 7x+2 9. Find AB. B. 12y A 10. Find mzABC. the rhombus.

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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"6 Find AB. (4y-1) 12y°. 7x+2 10. Find mZABC. Find the measure of each numbered angle in the rhombus. 11. 12. 70° 13. Select the word that best describes when each of the following statements are true, Select the correct answer for each lettered part. O always O sometimes never A. A rectangle is a parallelogram. O always O always O always O always sometimes B. A parallelogram is a rhombus. C. A square is a rhombus. D. A rhombus is a square. never sometimes O never sometimes never sometimes never E. A rhombus is a rectangle. 454 Lesson 3 Module 9 & Sinneta
Transcribed Image Text:"6 Find AB. (4y-1) 12y°. 7x+2 10. Find mZABC. Find the measure of each numbered angle in the rhombus. 11. 12. 70° 13. Select the word that best describes when each of the following statements are true, Select the correct answer for each lettered part. O always O sometimes never A. A rectangle is a parallelogram. O always O always O always O always sometimes B. A parallelogram is a rhombus. C. A square is a rhombus. D. A rhombus is a square. never sometimes O never sometimes never sometimes never E. A rhombus is a rectangle. 454 Lesson 3 Module 9 & Sinneta
14. Use properties of special parallelograms to complete the proof. Given: EFGH is a rectangle. J is the midpoint of EH. Prove: AFJG is isosceles. is ead Reasons Statements 1. EFGH is a rectangle. Jis the midpoint of EH. 1. Given 2. ZE and ZH are right angles. 2. Definition of rectangle 3. HZ37 4. EFGH is a parallelogram. 4. 5. 5. 6. 7. 8. 15. Explain the Error Find and explain the error in this paragraph proof. Then describe a way to correct the proof. Given: JKLM is a rhombus. Prove: JKLM is a parallelogram. Proof: It is given that JLKM is a rhombus. So, by the definition of a rhombus, JK E LM, and KL 2 MJ. If a quadrilateral is a parallelogram, then its opposite sides are congruent. So JKLM is a parallelogram. Lesson 3 455 mpoy
Transcribed Image Text:14. Use properties of special parallelograms to complete the proof. Given: EFGH is a rectangle. J is the midpoint of EH. Prove: AFJG is isosceles. is ead Reasons Statements 1. EFGH is a rectangle. Jis the midpoint of EH. 1. Given 2. ZE and ZH are right angles. 2. Definition of rectangle 3. HZ37 4. EFGH is a parallelogram. 4. 5. 5. 6. 7. 8. 15. Explain the Error Find and explain the error in this paragraph proof. Then describe a way to correct the proof. Given: JKLM is a rhombus. Prove: JKLM is a parallelogram. Proof: It is given that JLKM is a rhombus. So, by the definition of a rhombus, JK E LM, and KL 2 MJ. If a quadrilateral is a parallelogram, then its opposite sides are congruent. So JKLM is a parallelogram. Lesson 3 455 mpoy
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