-4x+5 As a partial fraction decomposition, we set equal to (2+3)* (-2-+z+1)(z–4) A-x+B C-x+D E-x+F G-x+H (-2 +3)' x2 +3 x2 +x+1 x-4 A B C D x2 +x+1 x-4 (22+3)² 2+3 A-x+B C-x+D Ex+F G x2 +x+1 (2 13)2 213 '21211'4 x-4 (2 +3)² A-x3 +B•x2 +C-x+D Ex-+F G-x+H I 2 +3 x2 +3 x2 +x+1 x-4 A-q³ +B•a? C-x+D E-x+F G 12 +3 x2 +x+1 x-4 (22 +3)
-4x+5 As a partial fraction decomposition, we set equal to (2+3)* (-2-+z+1)(z–4) A-x+B C-x+D E-x+F G-x+H (-2 +3)' x2 +3 x2 +x+1 x-4 A B C D x2 +x+1 x-4 (22+3)² 2+3 A-x+B C-x+D Ex+F G x2 +x+1 (2 13)2 213 '21211'4 x-4 (2 +3)² A-x3 +B•x2 +C-x+D Ex-+F G-x+H I 2 +3 x2 +3 x2 +x+1 x-4 A-q³ +B•a? C-x+D E-x+F G 12 +3 x2 +x+1 x-4 (22 +3)
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Related questions
Question
![-4x+5
As a partial fraction decomposition, we set
equal to
(2 +3)" (2² +=+1) (z–4)
E-x+F
G-x+H
x-4
A-x+B
C-x+D
22 +3
2 +x+1
A
B
C
D
(2-+3)²
x2 +3
x2+x+1
x-4
A-x+B
C-x+D
E-x+F
G
(2 13)2 213
2 +3
x2+x+1
x-4
A-23 +B•x² +C-x+D
G-x+H
Ex-+F
+
22 +3
x2 +x+1
x-4
+3
A-a3 +B-x2
C-x+D
E-x+F
G
(2-3)°
22 +3
22 +x+1
x-4
(22+3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1c140842-43f5-4a9d-9c50-01b756b87b16%2F358b8d17-5ffb-4522-a9c8-45f467e7fe6f%2Fu7lkj4j_processed.jpeg&w=3840&q=75)
Transcribed Image Text:-4x+5
As a partial fraction decomposition, we set
equal to
(2 +3)" (2² +=+1) (z–4)
E-x+F
G-x+H
x-4
A-x+B
C-x+D
22 +3
2 +x+1
A
B
C
D
(2-+3)²
x2 +3
x2+x+1
x-4
A-x+B
C-x+D
E-x+F
G
(2 13)2 213
2 +3
x2+x+1
x-4
A-23 +B•x² +C-x+D
G-x+H
Ex-+F
+
22 +3
x2 +x+1
x-4
+3
A-a3 +B-x2
C-x+D
E-x+F
G
(2-3)°
22 +3
22 +x+1
x-4
(22+3
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