²-4x+4>0

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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 Solve the quadratic inequalities.

The given inequality is:

\[ x^2 - 4x + 4 > 0 \]

This inequality represents a quadratic expression. To solve this inequality, we first need to analyze the quadratic equation \( x^2 - 4x + 4 = 0 \).

### Steps to solve the given quadratic inequality:

1. **Factor the Quadratic Expression:**
   \[ x^2 - 4x + 4 = (x - 2)^2 \]

2. **Set the Quadratic Expression Equal to Zero:**
   \[ (x - 2)^2 = 0 \]

   Solve for \( x \):
   \[ x - 2 = 0 \implies x = 2 \]

   This indicates that the quadratic expression has a repeated root at \( x = 2 \).

3. **Examine the Sign of the Expression:**
   Since \( (x - 2)^2 \) is a square term, it is always non-negative (\( \geq 0 \)). The equality holds at \( x = 2 \). For all other values of \( x \),  \( (x - 2)^2 \) is positive.

4. **Solve the Inequality:**
   For \( x^2 - 4x + 4 > 0 \), we need the expression to be positive:
   \[ (x - 2)^2 > 0 \]

   Since the square of any real number is non-negative and equal to zero only at \( x = 2 \), it is positive everywhere else. Therefore, the solution to the inequality is:
   \[ x \neq 2 \]

### Final Answer:
\[ x \in (-\infty, 2) \cup (2, \infty) \]

### Explanation:
The quadratic inequality \( x^2 - 4x + 4 > 0 \) holds true for all real values of \( x \) except \( x = 2 \). The expression equals zero at \( x = 2 \) because it is a perfect square.

This information is essential for understanding quadratic inequalities and their solutions.
Transcribed Image Text:The given inequality is: \[ x^2 - 4x + 4 > 0 \] This inequality represents a quadratic expression. To solve this inequality, we first need to analyze the quadratic equation \( x^2 - 4x + 4 = 0 \). ### Steps to solve the given quadratic inequality: 1. **Factor the Quadratic Expression:** \[ x^2 - 4x + 4 = (x - 2)^2 \] 2. **Set the Quadratic Expression Equal to Zero:** \[ (x - 2)^2 = 0 \] Solve for \( x \): \[ x - 2 = 0 \implies x = 2 \] This indicates that the quadratic expression has a repeated root at \( x = 2 \). 3. **Examine the Sign of the Expression:** Since \( (x - 2)^2 \) is a square term, it is always non-negative (\( \geq 0 \)). The equality holds at \( x = 2 \). For all other values of \( x \), \( (x - 2)^2 \) is positive. 4. **Solve the Inequality:** For \( x^2 - 4x + 4 > 0 \), we need the expression to be positive: \[ (x - 2)^2 > 0 \] Since the square of any real number is non-negative and equal to zero only at \( x = 2 \), it is positive everywhere else. Therefore, the solution to the inequality is: \[ x \neq 2 \] ### Final Answer: \[ x \in (-\infty, 2) \cup (2, \infty) \] ### Explanation: The quadratic inequality \( x^2 - 4x + 4 > 0 \) holds true for all real values of \( x \) except \( x = 2 \). The expression equals zero at \( x = 2 \) because it is a perfect square. This information is essential for understanding quadratic inequalities and their solutions.
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