= ( 4+x)-³. 00 n=0 00 00 118 00 (-1)^(n+1) (n + 2)x" in +3 2.4" (-1)^(n+4)! 2n! (-1)" (n+1) (n + 2) x^ 3 2-4³ (-1)" (n + 1) (n + 2) x²-1 +3 2. (n+3)! 2n! none of those
= ( 4+x)-³. 00 n=0 00 00 118 00 (-1)^(n+1) (n + 2)x" in +3 2.4" (-1)^(n+4)! 2n! (-1)" (n+1) (n + 2) x^ 3 2-4³ (-1)" (n + 1) (n + 2) x²-1 +3 2. (n+3)! 2n! none of those
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Related questions
Question
![Find the Maclaurin series for f(x) using the definition of a Maclaurin series.
f(x) = ( 4 + x)-³.
O (-1)" (n + 1) (n + 2) x^
2.4 +3
n=0
O(-1)(n+4)!
O (-1)" (n+1) (n + 2)x²
3
2.4
n=0
2n!
) (-1)" (n + 1) (n + 2)x"¯
n = 0
2.
00
(n+3)!
2n!
none of those](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8e9387cd-b429-46a6-9a29-5db6fa1b9f38%2Feb4cfec3-ce99-4fe2-b106-fef77cac4138%2F5ph1bj7_processed.png&w=3840&q=75)
Transcribed Image Text:Find the Maclaurin series for f(x) using the definition of a Maclaurin series.
f(x) = ( 4 + x)-³.
O (-1)" (n + 1) (n + 2) x^
2.4 +3
n=0
O(-1)(n+4)!
O (-1)" (n+1) (n + 2)x²
3
2.4
n=0
2n!
) (-1)" (n + 1) (n + 2)x"¯
n = 0
2.
00
(n+3)!
2n!
none of those
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