4PH3 ->> P4 + 6H₂ In a previous step, you calculated the rate of disappearance of PH3 at 6.67 x 10-3 M/s. What is the rate of appearance of P4 in the same time frame? Rate = -14 [PH] A[P4] At At Ratep₁ = [?] x 10¹²¹ M/s Coefficient (green) Exponent (yellow) Enter
4PH3 ->> P4 + 6H₂ In a previous step, you calculated the rate of disappearance of PH3 at 6.67 x 10-3 M/s. What is the rate of appearance of P4 in the same time frame? Rate = -14 [PH] A[P4] At At Ratep₁ = [?] x 10¹²¹ M/s Coefficient (green) Exponent (yellow) Enter
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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![### Calculating the Rate of Appearance of \( \text{P}_4 \)
Consider the following chemical reaction:
\[ 4 \text{PH}_3 \rightarrow \text{P}_4 + 6 \text{H}_2 \]
In a previous step, you calculated the rate of disappearance of \( \text{PH}_3 \) as \( 6.67 \times 10^{-3} \) M/s. The question at hand is: What is the rate of appearance of \( \text{P}_4 \) in the same time frame?
To find this, we use the reaction stoichiometry and rate relationships. The rate of reaction can be expressed as:
\[ \text{Rate} = -\frac{1}{4} \frac{\Delta [\text{PH}_3]}{\Delta t} = \frac{\Delta [\text{P}_4]}{\Delta t} \]
Given that the rate of disappearance of \( \text{PH}_3 \) is \( 6.67 \times 10^{-3} \text{ M/s} \), we use this information to calculate the rate of appearance of \( \text{P}_4 \).
\[ \text{Rate}_{\text{P}_4} = \boxed{[?]} \times 10^{\boxed{?}} \text{ M/s} \]
Finally, use the "Coefficient (green)" and "Exponent (yellow)" fields to input the appropriate values derived from the calculation to determine the exact rate of appearance of \( \text{P}_4 \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdfd84302-10e6-446d-ac4f-33b2622f5f16%2F05cbb56e-aa3d-41dc-93d1-5fda90cd5b4b%2Fo5v0c1a_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Calculating the Rate of Appearance of \( \text{P}_4 \)
Consider the following chemical reaction:
\[ 4 \text{PH}_3 \rightarrow \text{P}_4 + 6 \text{H}_2 \]
In a previous step, you calculated the rate of disappearance of \( \text{PH}_3 \) as \( 6.67 \times 10^{-3} \) M/s. The question at hand is: What is the rate of appearance of \( \text{P}_4 \) in the same time frame?
To find this, we use the reaction stoichiometry and rate relationships. The rate of reaction can be expressed as:
\[ \text{Rate} = -\frac{1}{4} \frac{\Delta [\text{PH}_3]}{\Delta t} = \frac{\Delta [\text{P}_4]}{\Delta t} \]
Given that the rate of disappearance of \( \text{PH}_3 \) is \( 6.67 \times 10^{-3} \text{ M/s} \), we use this information to calculate the rate of appearance of \( \text{P}_4 \).
\[ \text{Rate}_{\text{P}_4} = \boxed{[?]} \times 10^{\boxed{?}} \text{ M/s} \]
Finally, use the "Coefficient (green)" and "Exponent (yellow)" fields to input the appropriate values derived from the calculation to determine the exact rate of appearance of \( \text{P}_4 \).
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