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4n -1 Tabular Method Work 5n^3 -7n^2 20n^4 -28n^3 -5n^3 7n^2 On 0 0 -9 -36n 9 -1)(5n^3-7n^2-9)=20n^4+(-28n^3-5n^3)+(0+7n^2)+(-36n+0)+9 Answer for Tabular: _20n^4-33n^3+7n^2-36n+9_ Answer for Distributive: _20n^4-33n^3+7n^2-36n+9 Distributive Property work (4n-1)(5n^3-7n^2-9) =4n(5n^3-7n^2-9)-1(5n^3- 7n^2-9) 20n^4-28n^3-36n-5n^3+7n^2+9 20^4-28n^3-5n^3+7n^2-36n+9 Did you get the same answer? __Yes_ Why do you have to fill in a zero placeholder for the tabular method? 2

4n -1 Tabular Method Work 5n^3 -7n^2 20n^4 -28n^3 -5n^3 7n^2 On 0 0 -9 -36n 9 -1)(5n^3-7n^2-9)=20n^4+(-28n^3-5n^3)+(0+7n^2)+(-36n+0)+9 Answer for Tabular: _20n^4-33n^3+7n^2-36n+9_ Answer for Distributive: _20n^4-33n^3+7n^2-36n+9 Distributive Property work (4n-1)(5n^3-7n^2-9) =4n(5n^3-7n^2-9)-1(5n^3- 7n^2-9) 20n^4-28n^3-36n-5n^3+7n^2+9 20^4-28n^3-5n^3+7n^2-36n+9 Did you get the same answer? __Yes_ Why do you have to fill in a zero placeholder for the tabular method? 2

Algebra: Structure And Method, Book 1
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter2: Working With Real Numbers
Section2.9: Dividing Real Numbers
Problem 10MRE
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4n -1 Tabular Method Work 5n^3 -7n^2 20n^4 -28n^3 -5n^3 7n^2 On 0 0 -9 -36n 9 -1)(5n^3-7n^2-9)=20n^4+(-28n^3-5n^3)+(0+7n^2)+(-36n+0)+9 Answer for Tabular: _20n^4-33n^3+7n^2-36n+9_ Answer for Distributive: _20n^4-33n^3+7n^2-36n+9 Distributive Property work (4n-1)(5n^3-7n^2-9) =4n(5n^3-7n^2-9)-1(5n^3- 7n^2-9) 20n^4-28n^3-36n-5n^3+7n^2+9 20^4-28n^3-5n^3+7n^2-36n+9 Did you get the same answer? __Yes_ Why do you have to fill in a zero placeholder for the tabular method? 2
Transcribed Image Text:4n -1 Tabular Method Work 5n^3 -7n^2 20n^4 -28n^3 -5n^3 7n^2 On 0 0 -9 -36n 9 -1)(5n^3-7n^2-9)=20n^4+(-28n^3-5n^3)+(0+7n^2)+(-36n+0)+9 Answer for Tabular: _20n^4-33n^3+7n^2-36n+9_ Answer for Distributive: _20n^4-33n^3+7n^2-36n+9 Distributive Property work (4n-1)(5n^3-7n^2-9) =4n(5n^3-7n^2-9)-1(5n^3- 7n^2-9) 20n^4-28n^3-36n-5n^3+7n^2+9 20^4-28n^3-5n^3+7n^2-36n+9 Did you get the same answer? __Yes_ Why do you have to fill in a zero placeholder for the tabular method? 2
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