Below 0.3 K the slope of the 3He solid-liquid phase boundary is negativeUse the third law of thermodynamics to argue that the slope of the phase boundary must go to zero at T = O. (Note that the 4He solid-liquid phase boundary is essentially horizontal below 1 K.) 4He3HeSolidSolid3425.3Helium I(normal liquid)Helium IILiquid(superfluid)11.GasGas2.24.2 5.2 T (К)3.2 3.3 Т (K)Figure 5.13. Phase diagrams of "He (left) and He (right). Neither diagram isto scale, but qualitative relations between the diagrams are shown correctly. Notshown are the three different solid phases (crystal structures) of each isotope, orthe superfluid phases of He below 3 mK.Р (bar)Р (bar)

Using the clausius-clapeyron equation,we can find slope of boundary line…

Answered: 4He 3He Solid Solid 34 25.3 Helium I…

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Below 0.3 K the slope of the 3He solid-liquid phase boundary is negative

Use the third law of thermodynamics to argue that the slope of the phase boundary must go to zero at T = O. (Note that the 4He solid-liquid phase boundary is essentially horizontal below 1 K.)

4He
3He
Solid
Solid
34
25.3
Helium I
(normal liquid)
Helium II
Liquid
(superfluid)
1
1.
Gas
Gas
2.2
4.2 5.2 T (К)
3.2 3.3 Т (K)
Figure 5.13. Phase diagrams of "He (left) and He (right). Neither diagram is
to scale, but qualitative relations between the diagrams are shown correctly. Not
shown are the three different solid phases (crystal structures) of each isotope, or
the superfluid phases of He below 3 mK.
Р (bar)
Р (bar)

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