4b) Perform the 2's complement hexadecimal operation. Assume all numbers are 32 bits. Indicate the result and whether there is overflow or not. If the result is negative, show the hex value with the negative sign. 7ADEFDE2 EBED9328

Database System Concepts
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ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
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## Two's Complement Hexadecimal Subtraction

### Task:
Perform the 2’s complement hexadecimal operation. Assume all numbers are 32 bits. Indicate the result and whether there is overflow or not. If the result is negative, show the hex value with the negative sign.

### Given:
- **Minuend:** `7ADEFDE2`
- **Subtrahend:** `EBED9328`

### Steps:
1. **Convert the subtrahend to its 2's complement:** 
   - Invert the digits of `EBED9328` to get `14126CD7`.
   - Add 1 to the inverted result: `14126CD7` + 1 = `14126CD8`.

2. **Add the minuend and the 2's complement of the subtrahend:**
   - `7ADEFDE2` + `14126CD8` = `8EF16ABA`.

3. **Check for overflow:**
   - Since both initial numbers had different signs and the result sign matches with the minuend's sign, there is no overflow.

### Result:
- The operation yields `8EF16ABA` as the result.
- The result is positive, so there’s no need to indicate a negative sign.
- **No overflow occurred.**

This calculation demonstrates the process of performing a two’s complement subtraction with 32-bit hexadecimal numbers, carefully accounting for binary arithmetic rules and overflow conditions.
Transcribed Image Text:## Two's Complement Hexadecimal Subtraction ### Task: Perform the 2’s complement hexadecimal operation. Assume all numbers are 32 bits. Indicate the result and whether there is overflow or not. If the result is negative, show the hex value with the negative sign. ### Given: - **Minuend:** `7ADEFDE2` - **Subtrahend:** `EBED9328` ### Steps: 1. **Convert the subtrahend to its 2's complement:** - Invert the digits of `EBED9328` to get `14126CD7`. - Add 1 to the inverted result: `14126CD7` + 1 = `14126CD8`. 2. **Add the minuend and the 2's complement of the subtrahend:** - `7ADEFDE2` + `14126CD8` = `8EF16ABA`. 3. **Check for overflow:** - Since both initial numbers had different signs and the result sign matches with the minuend's sign, there is no overflow. ### Result: - The operation yields `8EF16ABA` as the result. - The result is positive, so there’s no need to indicate a negative sign. - **No overflow occurred.** This calculation demonstrates the process of performing a two’s complement subtraction with 32-bit hexadecimal numbers, carefully accounting for binary arithmetic rules and overflow conditions.
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