4Al(s) + 302(g)- - 2AI2O3(s) AH°rxn = -3351.4 kJ How much energy is transferred when 15.5 g of Al2O3 is produced? -51,900 kJ -3350 kJ O -1430 kJ -509 kJ -255 kJ
4Al(s) + 302(g)- - 2AI2O3(s) AH°rxn = -3351.4 kJ How much energy is transferred when 15.5 g of Al2O3 is produced? -51,900 kJ -3350 kJ O -1430 kJ -509 kJ -255 kJ
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Thermochemical Reaction Analysis
**Reaction:**
\[ 4\text{Al}(s) + 3\text{O}_2(g) \rightarrow 2\text{Al}_2\text{O}_3(s) \]
**Enthalpy Change:**
\[ \Delta H^\circ_{\text{rxn}} = -3351.4 \, \text{kJ} \]
**Question:**
How much energy is transferred when 15.5 g of \(\text{Al}_2\text{O}_3\) is produced?
**Options:**
- \(-51,900 \, \text{kJ}\)
- \(-3350 \, \text{kJ}\)
- \(-1430 \, \text{kJ}\) (Correct)
- \(-509 \, \text{kJ}\)
- \(-255 \, \text{kJ}\)
### Explanation
The text presents a thermochemical equation indicating that the formation of 2 moles of \(\text{Al}_2\text{O}_3\) from aluminum and oxygen releases \(3351.4 \, \text{kJ}\) of energy. The problem asks to calculate the energy transfer when only 15.5 g of \(\text{Al}_2\text{O}_3\) is produced, as opposed to 2 moles. The correct answer based on this calculation is \(-1430 \, \text{kJ}\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa3dab484-43c7-405a-8781-b23fe682a225%2F73261960-c2a6-48c5-b8ba-5c878c4aed75%2F8o2rb1d_processed.png&w=3840&q=75)
Transcribed Image Text:### Thermochemical Reaction Analysis
**Reaction:**
\[ 4\text{Al}(s) + 3\text{O}_2(g) \rightarrow 2\text{Al}_2\text{O}_3(s) \]
**Enthalpy Change:**
\[ \Delta H^\circ_{\text{rxn}} = -3351.4 \, \text{kJ} \]
**Question:**
How much energy is transferred when 15.5 g of \(\text{Al}_2\text{O}_3\) is produced?
**Options:**
- \(-51,900 \, \text{kJ}\)
- \(-3350 \, \text{kJ}\)
- \(-1430 \, \text{kJ}\) (Correct)
- \(-509 \, \text{kJ}\)
- \(-255 \, \text{kJ}\)
### Explanation
The text presents a thermochemical equation indicating that the formation of 2 moles of \(\text{Al}_2\text{O}_3\) from aluminum and oxygen releases \(3351.4 \, \text{kJ}\) of energy. The problem asks to calculate the energy transfer when only 15.5 g of \(\text{Al}_2\text{O}_3\) is produced, as opposed to 2 moles. The correct answer based on this calculation is \(-1430 \, \text{kJ}\).
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