4ac- 62 { Acos (VABC-B³² x) 2a y(x) = Ã cos + B sin y(x) = A cos bx ²x)} exp (-26) 2a 4ac- 62 2a We could also, for suitable new constants A and , write x +0) exp(-26) √4ac- 6² 2a
4ac- 62 { Acos (VABC-B³² x) 2a y(x) = Ã cos + B sin y(x) = A cos bx ²x)} exp (-26) 2a 4ac- 62 2a We could also, for suitable new constants A and , write x +0) exp(-26) √4ac- 6² 2a
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
How do I simplify the first equation to get the second equation?

Transcribed Image Text:√4ac
6²
/4ac
bx
x(x) = { Acos (Vªac = Bª₂) + B sin (Vªac = "²₂) } - (-5)
x) x)} exp(-26)
x
2a
2a
2a
We could also, for suitable new constants A and o, write
√4ac-b²
bx
cos (VARS = ² x + a) exp(-20)
2a
2a
y(x) = A cos
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