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4a. to get the dimensions of a closed right circular cylindrical can with the smallest surface area whose volume is 2π cm³, use the Lagrange multipliers.

4a. to get the dimensions of a closed right circular cylindrical can with the smallest surface area whose volume is 2π cm³, use the Lagrange multipliers.

Intermediate Algebra
Intermediate Algebra
10th Edition
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter8: Conic Sections
Section8.2: More Parabolas And Some Circles
Problem 63.2PS: By expanding (xh)2+(yk)2=r2, we obtain x22hx+h22ky+k2r2=0. When we compare this result to the form...
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4a. to get the dimensions of a closed right circular cylindrical can with the smallest surface area whose volume is 2π cm³, use the Lagrange multipliers. 4b. If w= In(4ry) — cos(2yz — 3), x = log(t), y = 4e²² and z = sin(t³ - 1). Find du. dt
Transcribed Image Text:4a. to get the dimensions of a closed right circular cylindrical can with the smallest surface area whose volume is 2π cm³, use the Lagrange multipliers. 4b. If w= In(4ry) — cos(2yz — 3), x = log(t), y = 4e²² and z = sin(t³ - 1). Find du. dt
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