49 packages are randomly selected from packages received by a parcel service. The sample has a mean weight of 24.0 olo pounds. Assume that o=2.0 pounds. What is the 95% confidence interval for the true mean weight, μ, of all packages received by the parcel service? O 23.3 to 24.7 pounds O 23.4 to 24.6 pounds O 23.5 to 24.5 pounds O 23.2 to 24.8 pounds X
49 packages are randomly selected from packages received by a parcel service. The sample has a mean weight of 24.0 olo pounds. Assume that o=2.0 pounds. What is the 95% confidence interval for the true mean weight, μ, of all packages received by the parcel service? O 23.3 to 24.7 pounds O 23.4 to 24.6 pounds O 23.5 to 24.5 pounds O 23.2 to 24.8 pounds X
MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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![### Statistical Analysis: Confidence Intervals
**Scenario:**
49 packages are randomly selected from packages received by a parcel service. The sample has a mean weight of 24.0 pounds. Assume that the standard deviation \( \sigma = 2.0 \) pounds. What is the 95% confidence interval for the true mean weight, \( \mu \), of all packages received by the parcel service?
**Options:**
- 23.3 to 24.7 pounds
- 23.4 to 24.6 pounds
- 23.5 to 24.5 pounds
- 23.2 to 24.8 pounds
**Explanation:**
A confidence interval is a range of values that is likely to contain the population mean with a certain level of confidence. This problem requires calculating a 95% confidence interval for the mean weight of all packages, using the sample mean and standard deviation provided.
**Calculations:**
To calculate the confidence interval, we use the formula for the confidence interval of the mean:
\[
\bar{x} \pm Z \left( \frac{\sigma}{\sqrt{n}} \right)
\]
Where:
- \( \bar{x} \) is the sample mean
- \( Z \) is the Z-score corresponding to the desired confidence level (1.96 for 95%)
- \( \sigma \) is the population standard deviation
- \( n \) is the sample size
**Visual Explanation:**
The image has no graphs or diagrams to explain, so focus is purely on textual explanation of the statistical concept of confidence intervals.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb4f1bd45-0584-49f4-9d42-60805b104190%2Ff7c6dea3-e5d6-4511-9a7d-f4aaa603855f%2Fghf8t19_processed.png&w=3840&q=75)
Transcribed Image Text:### Statistical Analysis: Confidence Intervals
**Scenario:**
49 packages are randomly selected from packages received by a parcel service. The sample has a mean weight of 24.0 pounds. Assume that the standard deviation \( \sigma = 2.0 \) pounds. What is the 95% confidence interval for the true mean weight, \( \mu \), of all packages received by the parcel service?
**Options:**
- 23.3 to 24.7 pounds
- 23.4 to 24.6 pounds
- 23.5 to 24.5 pounds
- 23.2 to 24.8 pounds
**Explanation:**
A confidence interval is a range of values that is likely to contain the population mean with a certain level of confidence. This problem requires calculating a 95% confidence interval for the mean weight of all packages, using the sample mean and standard deviation provided.
**Calculations:**
To calculate the confidence interval, we use the formula for the confidence interval of the mean:
\[
\bar{x} \pm Z \left( \frac{\sigma}{\sqrt{n}} \right)
\]
Where:
- \( \bar{x} \) is the sample mean
- \( Z \) is the Z-score corresponding to the desired confidence level (1.96 for 95%)
- \( \sigma \) is the population standard deviation
- \( n \) is the sample size
**Visual Explanation:**
The image has no graphs or diagrams to explain, so focus is purely on textual explanation of the statistical concept of confidence intervals.
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