49 measurements of a variable have been made, resulting in a mean of 9.491 and a population standard deviation, σ, of 1.212. Indicate whether any of the following values ​​can be rejected using the 2sm criterion: 9.357; 9.399; 9.577; 9.605?(A). Yes, 9.357 and 9.605 can be rejected(B). Yes, 9.357 can be rejected(C). Yes, 9.605 can be rejected(D). No, none should be rejected

9) The following results were obtained in the determination of Vitamin E mass in tablet samples. Sample 1 2 3 4 5 6 Weight of Vitamin E (mg) 249.1 249.9 251.2 250.2 244.8 251.0 i. Determine whether any data should be rejected or not at 90 % confidence level. ii. Calculate the mean and standard deviation of the data set above. ii. Express the mean weight of vitamin C at 99 % confidence interval.

A chemist obtained the following data for percent lindane in the triplicate analysis of an insecticide preparation: 7.23, 6.95, and 7.53. Calculate the 95% confidence interval for the mean of the three data, assuming the following criteria. (a) the only information about the precision of the method is the precision for the three data Confidence interval =  ±  % lindane (b) on the basis of long experience with the method, it is believed that s --> o = 0.26% lindane Confidence interval =  ±  % lindane

Estimate the absolute deviation(or uncertainty) for the results of the following calculations. Round each result so that it contains only significant digits. The numbers in parentheses are absolute standard deviations. Finally, write the answer and its uncertainty.a.) Y= 6.75 (± 0.03) + 0.843(±0.001) - 5.021 (±0.001) = 2.572b.) Y= 19.97(± 0.04) + 0.0030(±0.0001) + 4.29(±0.08) = 24.263c.) Y= 143(± 6) - 64(±3) = 5.9578 x10-21249 (±1) +77 (±8)

A powder was prepared containing 3.00% NaCN and 97.00% NaCl. A sample obtained from that mixture containing 7.374×10^5 particles weighs 10.0 g. Determine the number and percent relative standard deviation of NaCN particles from a sample of the mixture weighing 6.30 g. I need nNaCN particles and %RSD

Rewrite the number 3.123 56 (+0.167 89%) in the forms (a) number (6absolute uncertainty) and (b) number (+percent relative uncertainty) with an appropriate number of digits.

8) Two different analytical methods are compared for determining Ca. The following are two sets of data. Set 1 Set 2 155.779 155.784 155.787 155.787 155.813 155.765 155.781 155.793 i. i. Determine the mean and the standard deviation in Set 1. Calculate the 95% confidence limit for data in Set 1. Identify a possible outlier in Set 2. Use the Q-test to determine whether it can be retained or rejected at 95% confidence level. ii.

For the determination of iron in used jet engine oil, 30 analyzes with 3 repetitions each were made by atomic absorption method and the standard deviation was found s=2.4 µg Fe/mL. Since this standard deviation value is close to the ϭ value, the iron concentration of 18.5 µg Fe/mL(a) by a single analysis,(b) as the average of the two analyzes,(c) Calculate the 80% and 95% confidence intervals if found as the mean of four analyses.

Analysis of several plant-food preparations for potassium ion yielded the following data: Sample                                                     Percent K+1                                                             6.02, 6.04, 5.88, 6.06, 5.822                                                              5.29, 5.13, 5.14, 5.28, 5.20 The preparations were randomly drawn from the same population.(a) Find the mean and standard deviation s , variance , andCV for each sample.

Q1/ calculate the precision in confidence level 63% and 95% from these results (Arrange your answer in the same table) Element S (5) P 63% P 95% precision ppm Zn 74 83 83 Cu 27 24 24 Co 27 29 29 Ni 130 130 130 Pb 354 365 365 Cr 100 106 106 Sr 378 393 417 Mn 227 510 510 !!