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48. By constructing a Millman equivalent voltage source with respect to terminals x – y, find the voltage across 40 0 resistor in the figure shown. * 180 2 15 V 22.5 V수 7.5 V수 40 Ω 300 2 100 2 120 2 y O 3.6 V 20.77 W 2.4 V 58.64 W ww

48. By constructing a Millman equivalent voltage source with respect to terminals x – y, find the voltage across 40 0 resistor in the figure shown. * 180 2 15 V 22.5 V수 7.5 V수 40 Ω 300 2 100 2 120 2 y O 3.6 V 20.77 W 2.4 V 58.64 W ww

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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@47&48 Please help me answer this problem. Choose the correct answer from the given choices. NOTE: Show your solutions or answers why you've got or undergone this answer. BOX YOUR FINAL ANSWER. Make sure your answer is in the given choices. State whether the answer is Option A, B, C, or D. Type only your step by step solutions and answers here, do not handwritten. Failure to follow the above reminders and direction will be marked as not helpful. Thank you.
48. By constructing a Millman equivalent voltage source with respect to terminals x – y, find the voltage across 40 Q resistor in the figure shown. * 180 Ω 15 V 22.5 V+ 7.5 V= 40 Ω 300 2 100 2 120 2 y O 3.6 V 20.77 W 2.4 V 58.64 W
Transcribed Image Text:48. By constructing a Millman equivalent voltage source with respect to terminals x – y, find the voltage across 40 Q resistor in the figure shown. * 180 Ω 15 V 22.5 V+ 7.5 V= 40 Ω 300 2 100 2 120 2 y O 3.6 V 20.77 W 2.4 V 58.64 W
47. By constructing a Millman equivalent voltage source at terminals x – y, find the voltage across 5 Q in the circuit shown. 60 N 2 30 N R, = 5 N 120 V 30 V y O 1 V 4 V 5 V O 2 V
Transcribed Image Text:47. By constructing a Millman equivalent voltage source at terminals x – y, find the voltage across 5 Q in the circuit shown. 60 N 2 30 N R, = 5 N 120 V 30 V y O 1 V 4 V 5 V O 2 V
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