47. The Laplace distribution is discussed in Appendix 5–D. As noted there, the Laplace distribution could be a good choice for describing demand for slow-moving items and for fast-moving items with high variation. The cdf of the Laplace distribution is given by F(x) = 0.5[1 + sgn(x – µ)](1 – exp(-|x – u|/0), and the inverse of the cdf is given by F'(p) = µ – 0 sgn (p – 0.5) In (1 – 2 |p – 0.5 |), where sgn(x) is the sign ofx. The mean is u and the variance is 20². Since the inverse dis- tribution function can be written down explicitly, one does not have to resort to tables to solve newsvendor problems when demand follows the Laplace distribution. Solve Problem 10, part (a), assuming the demand for the EX123 follows a Laplace distribution with parameters µ = 60 and 0 = 3 V2 (which will give exactly the same mean and variance).

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47. The Laplace distribution is discussed in Appendix 5–D. As noted there, the Laplace
distribution could be a good choice for describing demand for slow-moving items
and for fast-moving items with high variation. The cdf of the Laplace distribution is
given by
F(x) = 0.5[1 + sgn(x – µ)](1 – exp(-|x – u|/0),
and the inverse of the cdf is given by
F'(p) = µ – 0 sgn (p – 0.5) In (1 – 2 |p – 0.5 |),
where sgn(x) is the sign ofx. The mean is u and the variance is 20². Since the inverse dis-
tribution function can be written down explicitly, one does not have to resort to tables to
solve newsvendor problems when demand follows the Laplace distribution.
Solve Problem 10, part (a), assuming the demand for the EX123 follows a Laplace
distribution with parameters µ = 60 and 0 = 3 V2 (which will give exactly the same
mean and variance).
Transcribed Image Text:47. The Laplace distribution is discussed in Appendix 5–D. As noted there, the Laplace distribution could be a good choice for describing demand for slow-moving items and for fast-moving items with high variation. The cdf of the Laplace distribution is given by F(x) = 0.5[1 + sgn(x – µ)](1 – exp(-|x – u|/0), and the inverse of the cdf is given by F'(p) = µ – 0 sgn (p – 0.5) In (1 – 2 |p – 0.5 |), where sgn(x) is the sign ofx. The mean is u and the variance is 20². Since the inverse dis- tribution function can be written down explicitly, one does not have to resort to tables to solve newsvendor problems when demand follows the Laplace distribution. Solve Problem 10, part (a), assuming the demand for the EX123 follows a Laplace distribution with parameters µ = 60 and 0 = 3 V2 (which will give exactly the same mean and variance).
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