47 PHYSE 40.0 cm 20.0 cm 80.0 cm Figure shows uniform solid cylinder 80.0 cm long and 40.0 cm in diameter, with a small spherical portion removed from it. The diameter of this removed portion is 20.0 cm and its center is 20.0 cm from one end of the cylinder. Find the center of gravity of the remaining portion if the center of the sphere lies on the axis of the cylinder. Formula: Vsphere = (pid^3)/6; Vcylinder = (pid^2h)/4; (Vcyl - Vsphere) xcg = (Vcyl xcyl – Vsphere xsphere)

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
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47
PHYS
40.0 cm
20.0 cm
80.0 cm
Figure shows uniform solid cylinder 80.0 cm long and 40.0 cm in diameter, with a small
spherical portion removed from it. The diameter of this removed portion is 20.0 cm and its
center is 20.0 cm from one end of the cylinder. Find the center of gravity of the remaining
portion if the center of the sphere lies on the axis of the cylinder.
Formula: Vsphere = (pid^3)/6; Vcylinder = (pid^2h)/4;
(Vcyl - Vsphere) xcg = (Vcyl xcyl – Vsphere xsphere)
%3D
Transcribed Image Text:47 PHYS 40.0 cm 20.0 cm 80.0 cm Figure shows uniform solid cylinder 80.0 cm long and 40.0 cm in diameter, with a small spherical portion removed from it. The diameter of this removed portion is 20.0 cm and its center is 20.0 cm from one end of the cylinder. Find the center of gravity of the remaining portion if the center of the sphere lies on the axis of the cylinder. Formula: Vsphere = (pid^3)/6; Vcylinder = (pid^2h)/4; (Vcyl - Vsphere) xcg = (Vcyl xcyl – Vsphere xsphere) %3D
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