47 2 100 2- 2.2 k2 560 2 Figure 5-5 The total resistance in the circuit in Figure 5-5 is 709.2 k2 A) B) C) D) 927 2 2907 Q 23.416.2 Q

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Q: 3. Determine the total resistance and the total current. 100V 1 + 1002 M 15.2. M 1502 500 1052 1022

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Q: +5 V Rc=5 k2 R = 12 k2 Cc R2 = 2 k2 RE = 0.5 k2 -5 V ww ww

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Q: Current through ammeter A2 and A3 in the figure below are 1/100 and 1/700 The reading of ammeter A1…

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Q: R4 330A RI 1.0KA R2 470A R6 1.0KA R7 680n R3 560A R8 1.5Kn 100V 100n R5

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Q: R1 R2 R3 R4 220 Q 220 Q 220 Q 220 Q w w +1 PSB 5 V

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Q: in step 2 is that 5r

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Q: Find the current through each resistors if C1= 552 C=32 %3D VT = 17V

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Q: R4 330 RI 1.0KA R2 470A R6 1.0Kn R7 680n R3 560A R8 1.5Kn 100V 100n R5

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Q: 4A 4A R2 = 30 R3 = 40 R1 = 30 E R4 R5 = 2R4

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Q: R1 R2 R4 R3 R5 R6 RT 3.

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Q: 17. What is the equivalent resistance of these resistance combinations? R4 R7 R1 R5 12 R2 un RB R6…

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Power Measurement

According to Blondel's theorem, the total power is measured with one less number of wattmeters than the number of wires present in the system. So, a single-phase and two-wire system will require one wattmeter and a single-phase and the three-wire system will require two wattmeters, and a three-phase and the three-wire system will also require two wattmeters and a three-phase and the four-wire system will require three wattmeter devices. The wattmeter is a device that measures power using one voltage and one current input as shown in the above figure. Multiple current or voltage input pair cables are used by many power analyzers and digital storage oscilloscopes (DSOs) for measuring watts, in effect within a single instrument acting as multiple wattmeters. It is possible to measure three-phase and four-wire power with one correctly specified power analyzer.