468 CHAPTER 14 The Fourier Integral end TransforAS sin(x) for -4sx<0 4. f(x)={cos(x) for 0 4 5. S(x)= * for-100 srs100 0 for jx) > 100 10 11
468 CHAPTER 14 The Fourier Integral end TransforAS sin(x) for -4sx<0 4. f(x)={cos(x) for 0 4 5. S(x)= * for-100 srs100 0 for jx) > 100 10 11
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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CHAPTER 14 The Fourier Integral End Transforms
sin(x) for-4sxs0
4. f(x)={cos(x) for 0 <x<4
1/2 for-5<x<1
8. f(x) ={1
for 1<x<5
for |x) > 4
for |x > 5
for-100 sxs100
0 for [x] > 100
9. f(x)=e-
10. f(x)= xe
11. Show that the Fourier integral of S(x)
5. S(x)=
6. f(x) =
[1x for- Sx< 2n
sin(@(1-x
Tim
for x<-n and for x> 2n
sin(x) for -3t <x<A
7. f(x)=-
for x<-37 and for x>A](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9fce6bd3-7852-4748-a7d0-10601967228b%2F6c704e42-76fc-4991-8822-32ad54619d74%2Fodzu0p_processed.jpeg&w=3840&q=75)
Transcribed Image Text:468
CHAPTER 14 The Fourier Integral End Transforms
sin(x) for-4sxs0
4. f(x)={cos(x) for 0 <x<4
1/2 for-5<x<1
8. f(x) ={1
for 1<x<5
for |x) > 4
for |x > 5
for-100 sxs100
0 for [x] > 100
9. f(x)=e-
10. f(x)= xe
11. Show that the Fourier integral of S(x)
5. S(x)=
6. f(x) =
[1x for- Sx< 2n
sin(@(1-x
Tim
for x<-n and for x> 2n
sin(x) for -3t <x<A
7. f(x)=-
for x<-37 and for x>A
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