464730 3214874.qx3zny? Jump to level 1 Integer númInputs is read from input. Given the integer vector average Temps with the size of numinputs, assign numMatches with the number of integers in userValues that are equal to 0. Ex: If the input is 3 74 0 88 then the output is: matchValue: 0, numMatches: 1 5 int main() { 6 7 8 9 10 11 12 13 14 15 16 17 18 19 vector average Temps; unsigned int i; int numInputs; int numMatches; cin >> numInputs; I // Creates a vector of size numInputs and initialize all values to 0 average Temps.resize(numInputs); for (i = 0; i < averageTemps.size(); ++i) { \ cin >> average Temps.at(i); } V Your code goes here */ CS Scanned with, CamchannelumMat rumMatches << endl; 1 2 3

464730 3214874.qx3zny? Jump to level 1 Integer númInputs is read from input. Given the integer vector average Temps with the size of numinputs, assign numMatches with the number of integers in userValues that are equal to 0. Ex: If the input is 3 74 0 88 then the output is: matchValue: 0, numMatches: 1 5 int main() { 6 7 8 9 10 11 12 13 14 15 16 17 18 19 vector average Temps; unsigned int i; int numInputs; int numMatches; cin >> numInputs; I // Creates a vector of size numInputs and initialize all values to 0 average Temps.resize(numInputs); for (i = 0; i < averageTemps.size(); ++i) { \ cin >> average Temps.at(i); } V Your code goes here */ CS Scanned with, CamchannelumMat rumMatches << endl; 1 2 3

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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a. Here is pseudocode for a program that inputs a value n from the user and theninserts n random numbers, ensuring that there are no duplicates:Input n from userCreate vector v of type intLoop i = 1 to nr = random integer between 0 and n-1Linearly search through v for value rif r is not in vector v then add r to the end of vEnd LoopPrint out number of elements added to v Implement this program with your own linear search routine and add wrap-per code that will time how long it takes to run. Test the program for different values of n. Depending on the speed of your system, you may need to inputlarge values for n so that the program takes at least one second to run. Here is asample that indicates how to calculate the difference in time (time.h is a librarythat should be available on your version of C++):#include <time.h>time_t start,end;double dif;time (&start); // Record start time// Rest of program goes here.time (&end); // Record end timedif = difftime(end,start);cout…
Integer numInputs is read from input. Given the integer vector hourlyScores with the size of numInputs, write a for loop to output the integers in the second half of hourlyScores in reverse order. Separate the integers with a vertical bar surrounded by spaces ("I Ex: If the input is 8 86 88 97 116 132 146 148 163 then the output is: 163 | 148 | 146 | 132 Note: The vector size is always even. int i; int numInputs; 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23} cin >> numInputs; // Creates a vector of size numInputs and initialize all values to 0 hourlyScores.resize(numInputs); for (i = 0; i > hourlyScores.at(i); } * Your code goes here */ cout << endl; return 0;
Write a function that displays an n-by-n matrix using the following header: void printMatrix(int n)Each element is 0 or 1, which is generated randomly. Write a test program that prompts the user to enter n and displays an n-by-n matrix.
Python Coding Exercise: Write a function that takes three parameters: a 2-D array arr, a row location i, a column location j and returns a float representing the fraction of neighbors around arr [i,j] # write your function here:def find_frac(arr,i,j):
Python numpy library functions to perform basic matrix operations are as follows.• C=numpy.add(A, B): Add two matrices A and B and store result in C.• C=numpy.subtract(A, B): Subtract matrix B from matrix A and store result in C.• C=numpy.divide(A, B): Divide matrix A by matrix B and store result in C.• C=numpy.multiply(A, B): Multiply matrix A by matrix B and store result in C.• C=numpy.sum(A): Form the sum of elements of matrix A and store result in c ∈ R.• C=numpy.sum(A, axis = 0): Form the column wise summation of matrix A andstore result in vector C.• C=numpy.sum(A, axis = 1): Form the row wise summation of matrix A, storeresult in vector C.Python code to show the implementation of these methods in a sample matrix.
Please help me in c++ program declare two characker arrays and takes thier input and add /0 at the end of both then store value of first char array in third array which terminates terminates array when reads /0 at end of first char array and start printing 2nd char array in same 3rd string and print /0 at the end of third string. Output: Enter first string: this is /0 Enter seond string: cat /0 third string: this is cat /0
Vector Arithmetics M A function named arithGym requires an input variable h, and returns three outputs: (1) column vector u, column vector z. and scalar variable count. The input variable h is a column vector of random numbers with values between 100 and 100. The length of h is also randomly chosen between 30 and 60 elements. Perform the following operations. 1. Calculate u with the same length as h that has evenly spaced values ranging from the minimum value in h to the maximum value in h. 2. Each element of column vector z is equal to the square of the corresponding element in h divided by 2 times the corresponding element in u 3. Compute the scalar variable count that counts the number of instances an element in z has a value less than the value of the corresponding element in h. Make sure to assign the results to the output variables as indicated Solve this problem using only vectorized code with no loops or if statements. Note the variable h is defined as a function input. Do not…
Integers are read from input and stored into a vector until 0 is read. If the vector's last element is odd, output the odd elements in the vector. Otherwise, output the even elements in the vector. End each number with a newline. Ex: If the input is -9 12 -6 1 0, the vector's last element is 1. Thus, the output is: -9 1 Note: (x % 2 != 0) returns true if x is odd. int value; int i; bool isodd; 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 } cin >> value; while (value != 0) { } for (i = 0; i > value; Check return 0; 1 Next level 2 X 1: Compare output 3 4 For input -9 12 -6 1 0, the vector elements are -9, 12, -6, and 1. The last element, 1, is odd. The odd elements in the vector, -9 and 1, are output, each on a new line. Not all tests passed. 2 V 3
Integers are read from input and stored into a vector until 0 is read. If the vector's last element is odd, output the odd elements in the vector. Otherwise, output the even elements in the vector. End each number with a newline. Ex: If the input is -9 12 -6 1 0, the vector's last element is 1. Thus, the output is: -9 1 Note: (x % 2!= 0) returns true if x is odd. 4 5 int main() { 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20} vector vect1; int value; int i; bool isodd; cin >> value; while (value != 0) { vect1.push_back(value); cin >> value; } V* Your code goes here */ return 0; 2 3
Please send me answer with in 10 min!! I will you rate you good for sure!! Please solve all the 4 parts!! Write a class named Homework in IntelliJ that implements:(1) A function that performs dot product between two vectors a and b:public static double dotProduct(double[] a, double[] b)(2) A function that performs matrix multiplication between aMat and bMat and returns theresult in cMatpublic static void matMultiply(double[][] aMat, double[][] bMat, double[][] cMat)(3) A function that takes a line (String) as input and breaks it up into words that may beseparated by space, comma or tab:public static String[] getLineWords(String line)(4) A main function that tests all the above functions and prints out the results. Code written (has errors, but this is the structure/ method I'm going for) public class Homework { public static double dotProduct(double[] a, double[] b) { double result = 0; for (int i = 0; i < a.length; i++) { result += a[i] * b[i]; } return result; } public static…
Java code: write a java code that can perform SQUARE-MATRIX-MULTIPLY-RECURSIVE. A; B(Strassen's Algorithms)/ and ordinary multiplication. The program should ask the user for input file and output file locations, and give output for both methods. It should also check if both outputs match and include error handing for incorrect Matrix Multiplication input.
Write a recursive function named binarySearch that accepts a reference to a sorted vector of integers and an integer target value and uses a recursive binary search algorithm to find and return an index at which that target value is found in the vector. If the target value is not found in the vector, return -1. The following code shows some example calls and their expected return values: // index 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16vector<int>v {-4, 2, 7, 10, 15, 20, 22, 25, 30, 36, 42, 50, 56, 68, 85, 92, 103};intindex=binarySearch(v, 42); // 10intindex=binarySearch(v, 66); // -1 You should assume that the vector's elements are already sorted; you do not need to handle the case of an unsorted vector. Your function must be recursive and must use a binary search algorithm. Do not use loops or auxiliary data structures.