4:585G56.ill 57%GECE 70...This document contains ink, shapes and i...GECE 704 HW84.1 Systems of ODEs as Models inEngineering Applications2. What happens in Example 4.1 if we replaceT₁ by a tank containing 200 gal of water and150 lb of fertilizer dissolved in it?2 gal/min2 gal/minΤ2System of tanks

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Answered: 4:58 5G 56.ill 57% GECE 70... This…

Algebra and Trigonometry (6th Edition)

6th Edition

ISBN:9780134463216

Author:Robert F. Blitzer

Publisher:Robert F. Blitzer

ChapterP: Prerequisites: Fundamental Concepts Of Algebra

Section: Chapter Questions

Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...

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ers 1. Calculate. (0,8)2 Example 2: (1.5)2 Example 1: = 1,5 x 1,5 = 0,8 x 0,8 or = 2.25 = 0,64 b. (0.2)2 C. (0.3)2 a. (0.6)2 %3D %3D 100 = 0,49 d. (0,1)2 e. (0,5)2 f. (0.4)2 or VIOO g. Add a, b, c and d. You may use a calculator. 2. Calculate. = 0,2 Example 1: (0,06)? (0,13)2 Example 2: = 0,06 x 0,06 = 0,0169 = 0,0036 a. (0,03)2 b. (0,05)2 C. (0,01)? d. (0,04)2 f. (0.16)2 e. (0,12)2
39% in 20m 1 20 CALENDAR Travel to Home Green Street Lumen.. Sign in or oToday at 1102 PM hm Rukayat BalogunUser Settings My Classes Log Out Forums Calendar Gradebook 0am Eall 2018 Assessment plications of Systems of Equation:s Due in 11 hours, 27 minutes, Due Fri 12/21/2018 10:00 am A chemist has 30% and 60% solutions of acid available. How many liters of each solution should be mixed to obtain 84 liters of 35% acid solution? liters of 30% acid liters of 60% acid Get help: Video Points possible 1 Unlimited attempt Message instructor about this a Ieense
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12:36 D all al + business math midter... Now we solve it using a special method: Multiply across the known corners, then divido by the third number And we get this: using the above method 7= (42 x 10)/ 20 = 420 / 20 =21 N:42 = 10:20 20N = 42 x 10 20N = 420 N= 420/20 N= 21 therefore 21:42 - 10:20 is proportion So you should draw the head 21 long. Therefore 21:42 = 10:20 is proportion because the product of 21 and 20 is the same as the product of 42 and 10 which is 420. PEXERCISE 3.4: Find the missing number in the lollowing 1. 4:6 6:N 2. 4:N = 10:15 3. N:4 = 25:20 4. 8:10 = N:15 5. 8:N = 40:45 6. N:30 = 28:42 7. 48:N = 16:15 8. 20:4 = N:2 9. 24:4 = N:3 10. 6:N= 8:20 11, 2:6 = 8:N 12. N:32 = 2:8 13. 4:5 - 12:N 14. B/N = 40/45 15. N/30 = 28/42 16. 48/N = 16/15 17. N:100 = 1:4 18. 5:N = 140:7 19. 6:N= 12:14 20. 5:3 = N:60 MAH BM Business Mathematical Modue i RMGumanoy/BRHodrgier 36/41 LESSON 4 GHAPTER 4 COMMISSION: NET PROCEEDS > Formulas Involvina Commission Problems II
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A certain city's power company charges their residents for electricity usage on a daily basis. There is a basic charge of 11.57 cents. For each day the first 10 kWh cost 4.81 cents per kWh and any additional kWhs are 9.69 per kWh. (A kWh, or kilowatt-hour, is a unit of energy.) (a) Complete the following table using the information provided above. kWhkWh 0 5 10 15 20 cost (dollars)cost (dollars) kWhkWh 25 30 35 40 cost (dollars)cost (dollars) (b) We can define a piecewise function f(x)f(x) where xx is the kWh used in a day and f(x)f(x) is the cost, in dollars. This function would have the form f(x)={g(x)h(x)ififx∈Ax∈Bf(x)={g(x)ifx∈Ah(x)ifx∈B What functions g(x)g(x) and h(x)h(x) make up the piecewise function f(x)f(x)? g(x)=g(x)= for A = h(x)=h(x)= for B = Hint: A and B are intervals. If an interval uses ±∞±∞ write inf or -inf . (c) Using the above function, what is the cost of 26 kWh? dollars. (d) For 3 dollars, what is the maximum kWh usage for one…
Physics written by hand.
D. Question 10 What is the solution to -(6m + 8) = 4(17 - m) ? %3D O 2 O 30 O -38 O 38 « Previous M
11:01 ¢ O Module 3 Pr.et Template Module 3 Problem Set Answer the following as detailed as possible. 1. If the growth rate of a culture of bacteria is proportional to the number of bacteria present. After 1 day, the population of bacteria is 1.25 times the original number, Within what interval of time will the number of bacteria (a) double? (b) triple? 2. The tank shown below contains 80 Ibs of salt dissolved in 500 gal of water. The inflow per minute is 20 Ib of salt dissolved in 20 gal of water. The gal/min of the uniform mixture. Find the time when the salt content y(t) in the tank reaches 95% of its limiting value (as t - co ). w is 20 3. Use the Greedy and Edge-Picking algorithms to find the Hamiltonian cycle with the least total weight in the complete graph shown below. 57 25 75 65 21 50 55

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