455 PEN Department of Natural Sciences " Lecture 2NOBrlg) - g) t Bralg) rate= CN Br gas phase decomposition of NOBR is second order in NOBR, with a rate constant of 0.810 M' s* at 10.0 C. If we start with 0.00400 M NOBR, how many seconds are needed to use up 0.00150 M ? ニ と+ t. CA]t [A O. wed up afteiDiOOLSOM ued up. 0t04 OU-0.0CISO OU-0.00I50=000250A o250 =ol0.810,t [0.o0050) O.Q400 つ50 O The rate constant for the decomposition of gaseous azomethane, CH3N=NCH3 N2+ C2H6 40.8min-1 0.0500 min after 2.00 g of CH3N=NCH3 is introduced. at 425 °C. Calculate the number of (moles of CH3N=NCH3 and N2 in a 1.00 L fl Utoden. 4.8mm-1R enEAコニードL +ln CA]。 8. -K +en CA] 9.0500 40.8 encOAsO I]-E4@ mm-5)+lno -3,3と Imol %3D -0.0333mol -2,04 2 0ogy. saill -5.40
455 PEN Department of Natural Sciences " Lecture 2NOBrlg) - g) t Bralg) rate= CN Br gas phase decomposition of NOBR is second order in NOBR, with a rate constant of 0.810 M' s* at 10.0 C. If we start with 0.00400 M NOBR, how many seconds are needed to use up 0.00150 M ? ニ と+ t. CA]t [A O. wed up afteiDiOOLSOM ued up. 0t04 OU-0.0CISO OU-0.00I50=000250A o250 =ol0.810,t [0.o0050) O.Q400 つ50 O The rate constant for the decomposition of gaseous azomethane, CH3N=NCH3 N2+ C2H6 40.8min-1 0.0500 min after 2.00 g of CH3N=NCH3 is introduced. at 425 °C. Calculate the number of (moles of CH3N=NCH3 and N2 in a 1.00 L fl Utoden. 4.8mm-1R enEAコニードL +ln CA]。 8. -K +en CA] 9.0500 40.8 encOAsO I]-E4@ mm-5)+lno -3,3と Imol %3D -0.0333mol -2,04 2 0ogy. saill -5.40
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question 5
![455
PEN
Department of Natural Sciences
" Lecture
2NOBrlg) - g) t Bralg)
rate= CN Br
gas phase decomposition of NOBR is second order in NOBR, with a rate constant of 0.810 M' s* at
10.0 C. If we start with 0.00400 M NOBR, how many seconds are needed to use up 0.00150 M ?
ニ と+
t.
CA]t
[A
O.
wed up afteiDiOOLSOM ued up.
0t04 OU-0.0CISO
OU-0.00I50=000250A
o250
=ol0.810,t
[0.o0050)
O.Q400
つ50
O The rate constant for the decomposition of gaseous azomethane, CH3N=NCH3 N2+ C2H6
40.8min-1
0.0500 min after 2.00 g of CH3N=NCH3 is introduced.
at 425 °C. Calculate the number of (moles of CH3N=NCH3 and N2 in a 1.00 L fl
Utoden.
4.8mm-1R
enEAコニードL +ln CA]。
8.
-K +en CA]
9.0500
40.8
encOAsO
I]-E4@ mm-5)+lno
-3,3と
Imol
%3D
-0.0333mol
-2,04
2 0ogy.
saill
-5.40](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3f94b6c4-8026-41b5-a2ce-ea2500e29589%2Fc214dbed-12cf-4972-86c9-e9ec5414538f%2Fmbczt0m.jpeg&w=3840&q=75)
Transcribed Image Text:455
PEN
Department of Natural Sciences
" Lecture
2NOBrlg) - g) t Bralg)
rate= CN Br
gas phase decomposition of NOBR is second order in NOBR, with a rate constant of 0.810 M' s* at
10.0 C. If we start with 0.00400 M NOBR, how many seconds are needed to use up 0.00150 M ?
ニ と+
t.
CA]t
[A
O.
wed up afteiDiOOLSOM ued up.
0t04 OU-0.0CISO
OU-0.00I50=000250A
o250
=ol0.810,t
[0.o0050)
O.Q400
つ50
O The rate constant for the decomposition of gaseous azomethane, CH3N=NCH3 N2+ C2H6
40.8min-1
0.0500 min after 2.00 g of CH3N=NCH3 is introduced.
at 425 °C. Calculate the number of (moles of CH3N=NCH3 and N2 in a 1.00 L fl
Utoden.
4.8mm-1R
enEAコニードL +ln CA]。
8.
-K +en CA]
9.0500
40.8
encOAsO
I]-E4@ mm-5)+lno
-3,3と
Imol
%3D
-0.0333mol
-2,04
2 0ogy.
saill
-5.40
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