45. The weight of an object is inversely proportional to the square of its distance from the center of the Earth. At sea level (6 400 km from the center of the Earth), a cosmonaut weighs 110 kg. Find his weight when he is 210 km above the surface of the Earth.
45. The weight of an object is inversely proportional to the square of its distance from the center of the Earth. At sea level (6 400 km from the center of the Earth), a cosmonaut weighs 110 kg. Find his weight when he is 210 km above the surface of the Earth.
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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![45. The weight of an object is inversely proportional to the square of its distance from the center of the
Earth, At sea level (6 400 km from the center of the Earth), a cosmonaut weighs 110 kg. Find his weight
when he is 210 km above the surface of the Earth.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F35b07bd5-0223-4f95-beb5-9f5de146f164%2Fa7e8f30b-3d44-4b4e-9271-a0e1cdb4baf2%2F16z68zr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:45. The weight of an object is inversely proportional to the square of its distance from the center of the
Earth, At sea level (6 400 km from the center of the Earth), a cosmonaut weighs 110 kg. Find his weight
when he is 210 km above the surface of the Earth.
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