-45 + 7(x + 2) - 6x (no justification needed) = -45+ (7x + 14) - 6x = -45+ (14 + 7x) - 6x = (-45 + 14) + 7x - 6x =-31 + 7x - 6x (no justification needed) = -31 + (7-6)x = -31 + 1x (no justification needed) = -31 + x = x + (-31)
-45 + 7(x + 2) - 6x (no justification needed) = -45+ (7x + 14) - 6x = -45+ (14 + 7x) - 6x = (-45 + 14) + 7x - 6x =-31 + 7x - 6x (no justification needed) = -31 + (7-6)x = -31 + 1x (no justification needed) = -31 + x = x + (-31)
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
Explain each step, excluding those that are labeled as “no justification needed.” For each step, use a property of the real numbers and explain how the property is being applied.
This is for part 2 of the picture
Transcribed Image Text:Task 2
Part 1
Part 2
Part 3
A = 6
B = 8
4
C = 3√675
15
23
21
D = 4√27
E = 3√7
11
5
-45 + 7(x + 2) — 6x (no justification needed)
= -45+ (7x + 14) - 6x
= -45+ (14 + 7x) - 6x
= (-45 + 14) + 7x - 6x
=-31 + 7x- 6x (no justification needed)
12
3
4√5
√16
27
= -31+ (7-6)x
= -31 + 1x (no justification needed)
= -31 + x
= x + (-31)
√28
-5.823
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