44% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the number of U.S. adults who have very little confidence in newspapers is (a) exactly five, (b) at leas six, and (c) less than four. (a) P(5) = (Round to three decimal places as needed.) %3D (b) P(x =6) = . | (Round to three decimal places as needed.) %3D (c) P(x<4)=| (Round to three decimal places as needed.) %3D
44% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the number of U.S. adults who have very little confidence in newspapers is (a) exactly five, (b) at leas six, and (c) less than four. (a) P(5) = (Round to three decimal places as needed.) %3D (b) P(x =6) = . | (Round to three decimal places as needed.) %3D (c) P(x<4)=| (Round to three decimal places as needed.) %3D
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![**Title: Probability of U.S. Adults' Confidence in Newspapers**
**Introduction:**
In this lesson, we will discuss how to determine probabilities related to survey data concerning U.S. adults' confidence in newspapers. According to the data, 44% of U.S. adults have very little confidence in newspapers. We will explore the probability of specific outcomes when a sample of 10 U.S. adults is randomly selected.
**Problem Statement:**
Given that 44% of U.S. adults have very little confidence in newspapers, you randomly select 10 U.S. adults. Find the probability that the number of U.S. adults who have very little confidence in newspapers is:
(a) Exactly five,
(b) At least six, and
(c) Less than four.
**Instructions:**
For each part of the problem, you will need to round your answers to three decimal places as needed.
**Part (a):**
Find the probability that exactly 5 out of the 10 U.S. adults selected have very little confidence in newspapers.
\[ P(X = 5) = \]
**Part (b):**
Calculate the probability that at least 6 of the selected U.S. adults have very little confidence in newspapers.
\[ P(X \geq 6) = \]
**Part (c):**
Determine the probability that fewer than 4 of the selected U.S. adults have very little confidence in newspapers.
\[ P(X < 4) = \]
**Solution Steps:**
1. **Identify Parameters:**
- Probability of success \( p = 0.44 \)
- Number of trials \( n = 10 \)
- Random variable \( X \sim \text{Binomial}(n, p) \)
2. **Binomial Formula:**
\[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \]
3. **Use of Binomial Table or Software:**
To ease calculations, use a binomial probability table, a calculator, or statistical software.
4. **Calculation Examples:**
- For part (a), calculate \( P(X = 5) \) using the binomial formula.
- For part (b), sum the probabilities of \( X = 6 \) to \( X = 10 \) using the binomial formula or cumulative binomial distribution.
- For part (c),](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6f3c0317-a018-4411-a1b9-6d16a487273e%2F16601f63-4c38-4bfe-a575-5c03bb57fdf9%2Fl6f2jms_reoriented.jpeg&w=3840&q=75)
Transcribed Image Text:**Title: Probability of U.S. Adults' Confidence in Newspapers**
**Introduction:**
In this lesson, we will discuss how to determine probabilities related to survey data concerning U.S. adults' confidence in newspapers. According to the data, 44% of U.S. adults have very little confidence in newspapers. We will explore the probability of specific outcomes when a sample of 10 U.S. adults is randomly selected.
**Problem Statement:**
Given that 44% of U.S. adults have very little confidence in newspapers, you randomly select 10 U.S. adults. Find the probability that the number of U.S. adults who have very little confidence in newspapers is:
(a) Exactly five,
(b) At least six, and
(c) Less than four.
**Instructions:**
For each part of the problem, you will need to round your answers to three decimal places as needed.
**Part (a):**
Find the probability that exactly 5 out of the 10 U.S. adults selected have very little confidence in newspapers.
\[ P(X = 5) = \]
**Part (b):**
Calculate the probability that at least 6 of the selected U.S. adults have very little confidence in newspapers.
\[ P(X \geq 6) = \]
**Part (c):**
Determine the probability that fewer than 4 of the selected U.S. adults have very little confidence in newspapers.
\[ P(X < 4) = \]
**Solution Steps:**
1. **Identify Parameters:**
- Probability of success \( p = 0.44 \)
- Number of trials \( n = 10 \)
- Random variable \( X \sim \text{Binomial}(n, p) \)
2. **Binomial Formula:**
\[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \]
3. **Use of Binomial Table or Software:**
To ease calculations, use a binomial probability table, a calculator, or statistical software.
4. **Calculation Examples:**
- For part (a), calculate \( P(X = 5) \) using the binomial formula.
- For part (b), sum the probabilities of \( X = 6 \) to \( X = 10 \) using the binomial formula or cumulative binomial distribution.
- For part (c),
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