メニ44 LBz 2x+%=105 17) mZ3=(2x – 6)(x-4) 34 mZ5 5(5x + 3)- (2x²-42) Determine the value of x so that line l will be parallel to line m. 16 m<3+mL5z180° (2x-6)(x-4)+5(5x+3)-(2x2-42)-120 2入ー8x-6x+24+25x+15-2x2+42=120 8, 11x=180-81 lメニタタ १९१ 18) Given: XM bisects YXZ and YMZ. Prove: XM bisects ZYKZ statements reasons メMbisects 2x2 Gver Y M. Prove: PQ || SR 19) Given: PS = RQ; PQ = RS reasons statements Gven 1/PCERQ; PO 2)5QシS0 3)APQS=ASQR 2).7olentiny 3SSS 4)CPCTC
メニ44 LBz 2x+%=105 17) mZ3=(2x – 6)(x-4) 34 mZ5 5(5x + 3)- (2x²-42) Determine the value of x so that line l will be parallel to line m. 16 m<3+mL5z180° (2x-6)(x-4)+5(5x+3)-(2x2-42)-120 2入ー8x-6x+24+25x+15-2x2+42=120 8, 11x=180-81 lメニタタ १९१ 18) Given: XM bisects YXZ and YMZ. Prove: XM bisects ZYKZ statements reasons メMbisects 2x2 Gver Y M. Prove: PQ || SR 19) Given: PS = RQ; PQ = RS reasons statements Gven 1/PCERQ; PO 2)5QシS0 3)APQS=ASQR 2).7olentiny 3SSS 4)CPCTC
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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#18 please thanks
![メニ44
LBz 2x+%=105
17) mZ3=(2x – 6)(x-4)
34 mZ5 5(5x + 3)- (2x²-42)
Determine the value of x so that line l will be parallel to line m.
16
m<3+mL5z180°
(2x-6)(x-4)+5(5x+3)-(2x2-42)-120
2入ー8x-6x+24+25x+15-2x2+42=120
8,
11x=180-81
lメニタタ
१९१
18) Given: XM bisects YXZ and YMZ.
Prove: XM bisects ZYKZ
statements
reasons
メMbisects 2x2
Gver
Y
M.
Prove: PQ || SR
19) Given: PS = RQ; PQ = RS
reasons
statements
Gven
1/PCERQ; PO
2)5QシS0
3)APQS=ASQR
2).7olentiny
3SSS
4)CPCTC](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5bbe15d5-05c4-4aea-a090-ae763138d27c%2Ffe384846-09e3-4240-a8e7-6ae58765ef9a%2Fstt7a2r.jpeg&w=3840&q=75)
Transcribed Image Text:メニ44
LBz 2x+%=105
17) mZ3=(2x – 6)(x-4)
34 mZ5 5(5x + 3)- (2x²-42)
Determine the value of x so that line l will be parallel to line m.
16
m<3+mL5z180°
(2x-6)(x-4)+5(5x+3)-(2x2-42)-120
2入ー8x-6x+24+25x+15-2x2+42=120
8,
11x=180-81
lメニタタ
१९१
18) Given: XM bisects YXZ and YMZ.
Prove: XM bisects ZYKZ
statements
reasons
メMbisects 2x2
Gver
Y
M.
Prove: PQ || SR
19) Given: PS = RQ; PQ = RS
reasons
statements
Gven
1/PCERQ; PO
2)5QシS0
3)APQS=ASQR
2).7olentiny
3SSS
4)CPCTC
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