4242 Problem 2 - Independent Practice. Solve for one variable by substitution and plu back in to solve for the other variable. (Double check your answer). 4X=2x+4 (40-8 2x + 16 = -8 85-8 a. x = 2y + 4 4y - 8=x C. -3x+9= 4y x=y=3 y=8x₂ Y=8(1) X=-=8x²8 88 -X=- - 3x + 4 = 4 x (9-3 3XX 9+4 = -3 b. y=-z 5z + 5y = d. 1 2 2y + y=42-1
4242 Problem 2 - Independent Practice. Solve for one variable by substitution and plu back in to solve for the other variable. (Double check your answer). 4X=2x+4 (40-8 2x + 16 = -8 85-8 a. x = 2y + 4 4y - 8=x C. -3x+9= 4y x=y=3 y=8x₂ Y=8(1) X=-=8x²8 88 -X=- - 3x + 4 = 4 x (9-3 3XX 9+4 = -3 b. y=-z 5z + 5y = d. 1 2 2y + y=42-1
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Related questions
Question
I need help on substitution x = 2y + 4 and 4y - 8 = x

Transcribed Image Text:(-3-22)
Problem 2- Independent Practice. Solve for one variable by substitution and plug the answer
back in to solve for the other variable. (Double check your answer).
4X=2x+4 (40)
1-ho so
2x + 16 = -8
¥8:-8
88
[x = 8)
a.
x = 2y + 4
4y - 8 = x
C.
-3x+9 = 4y
x=y-3
Y=8x
Y=8(1)
-2016
to no
NEJE
12/12 (3)
4242
y=-8
-3x+9=4x (0-3
3X + 9+4 =-3
b.
2
y=-z
5x + 5y=10
2y +4
y=42-1
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